I'm trying to find the first day of the month in python with one condition: if my current date passed the 25th of the month, then the first date variable will hold the first date of the next month instead of the current month. I'm doing the following: import datetime
todayDate = datetime.date.today()
if (todayDate - todayDate.replace(day=1)).days > 25:
x= todayDate + datetime.timedelta(30)
x.replace(day=1)
print x
else:
print todayDate.replace(day=1)
is there a cleaner way for doing this?
Mel 5,56810 gold badges39 silver badges42 bronze badges asked
May 23, 2016 at 16:42 2 Can be done on the same line using date.replace : from datetime import datetime
datetime.today().replace(day=1)
cglacet 7,3003 gold badges39 silver badges53 bronze badges answered Jul 23, 2017 at 15:40
5 This is a pithy solution. import datetime
todayDate = datetime.date.today()
if todayDate.day > 25:
todayDate += datetime.timedelta(7)
print todayDate.replace(day=1)
One thing to note with the original code example is that using timedelta(30) will cause trouble if you are testing the last day of January. That is why I am using a 7-day delta. answered May 23, 2016 at 17:05
andrewandrew 3,8291 gold badge23 silver
badges38 bronze badges 1 Use
dateutil. from datetime import date
from dateutil.relativedelta import relativedelta
today = date.today()
first_day = today.replace(day=1)
if today.day > 25:
print(first_day + relativedelta(months=1))
else:
print(first_day)
answered May 23, 2016 at 16:55 lampslavelampslave 1,32514 silver badges18 bronze badges 1 from datetime import datetime
date_today = datetime.now()
month_first_day = date_today.replace(day=1, hour=0, minute=0, second=0, microsecond=0)
print(month_first_day)
answered Dec 13, 2018 at 7:24 Balaji.J.BBalaji.J.B 5386 silver badges14 bronze badges 1 Use arrow. import arrow
arrow.utcnow().span('month')[0]
answered Jul 17, 2018 at 10:03 ImPerat0R_ImPerat0R_ 5538 silver badges8 bronze badges
This could be an alternative to Gustavo Eduardo Belduma's answer: import datetime
first_day_of_the_month = datetime.date.today().replace(day=1)
answered Apr 9, 2020 at 7:54
tjurkantjurkan 3614 silver badges7 bronze
badges 1 Yes, first set a datetime to the start of the current month. Second test if current date day > 25 and get a true/false on
that. If True then add add one month to the start of month datetime object. If false then use the datetime object with the value set to the beginning of the month. import datetime
from dateutil.relativedelta import relativedelta
todayDate = datetime.date.today()
resultDate = todayDate.replace(day=1)
if ((todayDate - resultDate).days > 25):
resultDate = resultDate + relativedelta(months=1)
print resultDate
answered May 23, 2016 at 16:56
mba12mba12 2,5226 gold badges34 silver badges52 bronze badges The arrow module will steer you around and away from subtle mistakes, and it's easier to use that older products. import arrow
def cleanWay(oneDate):
if currentDate.date().day > 25:
return currentDate.replace(months=+1,day=1)
else:
return currentDate.replace(day=1)
currentDate = arrow.get('25-Feb-2017', 'DD-MMM-YYYY')
print (currentDate.format('DD-MMM-YYYY'), cleanWay(currentDate).format('DD-MMM-YYYY'))
currentDate = arrow.get('28-Feb-2017', 'DD-MMM-YYYY')
print (currentDate.format('DD-MMM-YYYY'), cleanWay(currentDate).format('DD-MMM-YYYY'))
In this case there is no need for you to consider the varying lengths of months, for instance. Here's the output from this script. 25-Feb-2017 01-Feb-2017
28-Feb-2017 01-Mar-2017
answered
Feb 22, 2017 at 14:41 Bill BellBill Bell 20.4k5 gold badges42 silver badges57 bronze badges 1 I
found a clean way to do this is to create a datetime object using the month and year attributes of todayDate, with days set to 1 i.e. import datetime
todayDate = datetime.date.today()
firstOfMon = datetime.date(todayDate.year, todayDate.month, 1)
answered Sep 24, 2021 at 11:05 You can use dateutil.rrule: In [1]: from dateutil.rrule import *
In [2]: rrule(DAILY, bymonthday=1)[0].date()
Out[2]: datetime.date(2018, 10, 1)
In [3]: rrule(DAILY, bymonthday=1)[1].date()
Out[3]: datetime.date(2018, 11, 1)
answered
Sep 21, 2018 at 8:06 dtatarkindtatarkin 1,0217 silver badges6 bronze badges One-liner: from datetime import datetime, timedelta
last_month=(datetime.now().replace(day=1) - timedelta(days=1)).replace(day=1)
answered Dec 7, 2021 at 10:32 My solution to find the first and last day of the current month: def find_current_month_last_day(today: datetime) -> datetime:
if today.month == 2:
return today.replace(day=28)
if today.month in [4, 6, 9, 11]:
return today.replace(day=30)
return today.replace(day=31)
def current_month_first_and_last_days() -> tuple:
today = datetime.now().replace(hour=0, minute=0, second=0, microsecond=0)
first_date = today.replace(day=1)
last_date = find_current_month_last_day(today)
return first_date, last_date
answered Oct 22, 2019 at 10:17
mhyousefimhyousefi 9042 gold badges12
silver badges29 bronze badges First day of next month: from datetime import datetime
class SomeClassName(models.Model):
if datetime.now().month == 12:
new_start_month = 1
else:
new_start_month = datetime.now().month + 1
Then we replace the month and the day start_date = models.DateField(default=datetime.today().replace(month=new_start_month, day=1, hour=0, minute=0, second=0, microsecond=0))
answered
Jul 22, 2020 at 15:40 Inspired by Jouberto's and @akx's answers (elsewhere), oneliners without any dependencies: now = datetime.datetime.now(tz=ZoneInfo("UTC"))
this_month = now.replace(day=1, hour=0, minute=0, second=0, microsecond=0)
next_month = (this_month.replace(day=28) + datetime.timedelta(days=4)).replace(day=1)
last_month = (this_month.replace(day=1) - datetime.timedelta(days=1)).replace(day=1)
answered Sep 5 at 12:53 Aapo RistaAapo Rista 1111 silver badge4 bronze
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