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Hollow rectangle star pattern :
The task is print below hollow pattern of given dimension.
********************
* *
* *
* *
* *
********************
Explanation:
- Input number of rows and columns.
- For rows of rectangle run the outer loop from 1 to rows.
for (i = 1; i < = rows; i++)
- For column of rectangle run the inner loop from 1 to columns.
for (j = 1; j < = columns; j++)
- Print star for first or last row or for first or last column, otherwise print blank space.
- After printing all columns of a row, print new line after inner loop.
C++
#include <bits/stdc++.h>
using
namespace std;
void print_rectangle(int n, int m)
{
int i, j;
for (i = 1; i <= n; i++)
{
for (j = 1; j <= m; j++)
{
if (i == 1 || i == n ||
j == 1 || j == m)
cout << "*";
else
cout << " ";
}
cout << endl;
}
}
int main()
{
int rows = 6, columns = 20;
print_rectangle(rows, columns);
return 0;
}
C
#include <stdio.h>
void print_rectangle(int n, int m)
{
int i, j;
for (i = 1; i <= n; i++)
{
for (j = 1; j <= m; j++)
{
if (i==1 || i==n || j==1 || j==m)
printf("*");
else
printf(" ");
}
printf("\n");
}
}
int main()
{
int rows = 6, columns = 20;
print_rectangle(rows, columns);
return 0;
}
Java
import java.io.*;
class GFG {
static void print_rectangle(int n, int m)
{
int i, j;
for
(i = 1; i <= n; i++)
{
for (j = 1; j <= m; j++)
{
if (i == 1 || i == n ||
j == 1 || j == m)
System.out.print("*");
else
System.out.print(" ");
}
System.out.println();
}
}
public static void main(String args[])
{
int
rows = 6, columns = 20;
print_rectangle(rows, columns);
}
}
Python3
def print_rectangle(n, m) :
for i in range(1, n+1) :
for j in range(1, m+1) :
if (i == 1 or i == n or
j ==
1 or j == m) :
print("*", end="")
else :
print(" ", end="")
print()
rows = 6
columns = 20
print_rectangle(rows, columns)
C#
using System;
public class GFG
{
static void print_rectangle(int
n, int m)
{
int i, j;
for (i = 1; i <= n; i++)
{
for (j = 1; j <= m; j++)
{
if (i == 1 || i == n ||
j == 1 || j == m)
Console.Write("*");
else
Console.Write(" ");
}
Console.WriteLine();
}
}
public static void
Main()
{
int rows = 6, columns = 20;
print_rectangle(rows, columns);
}
}
PHP
<?php
function print_rectangle($n, $m)
{
$i;
$j;
for ($i = 1; $i <= $n; $i++)
{
for ($j
= 1; $j <= $m; $j++)
{
if ($i == 1 || $i == $n ||
$j == 1 || $j == $m)
echo("*");
else
echo(" ");
}
echo("\n");
}
}
$rows
= 6;
$columns = 20;
print_rectangle($rows, $columns);
?>
Javascript
<script>
function print_rectangle(n, m)
{
var i, j;
for (i = 1; i <= n; i++)
{
for (j = 1; j <= m; j++)
{
if (i == 1 || i == n || j == 1 || j == m)
document.write("*");
else
document.write(" ");
}
document.write("<br>");
}
}
var rows = 6,
columns = 20;
print_rectangle(rows, columns);
</script>
Output:
********************
* *
* *
* *
* *
********************
Time Complexity: O(m * n), where m and n represents the given inputs.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
Hollow square star pattern :
********
* *
* *
* *
* *
* *
* *
********
Explanation:
- Input number of rows.
- For rows, an outer loop from 1 to N.
- For columns, an inner loop from 1 to N
- Inside inner loop print star for first and last row or for first and last column. Which is print star
if i == 1 or i == N or j == 1 or j == N
- otherwise print space.
- After printing all columns of a row, print a blank line after inner loop.
C++
#include <bits/stdc++.h>
using namespace std;
void print_square(int n)
{
int i, j;
for (i = 1; i <= n; i++)
{
for (j = 1; j <= n; j++)
{
if (i==1 || i==n || j==1 || j==n)
cout << "*";
else
cout << " ";
}
cout << "\n";
}
}
int
main()
{
int rows = 8;
print_square(rows);
return 0;
}
C
#include <stdio.h>
void print_square(int n)
{
int i, j;
for (i = 1; i <= n; i++)
{
for (j = 1; j <= n; j++)
{
if (i==1 || i==n || j==1 || j==n)
printf("*");
else
printf(" ");
}
printf("\n");
}
}
int main()
{
int rows = 8;
print_square(rows);
return 0;
}
Java
import java.io.*;
class GFG {
static void print_square(int n)
{
int
i, j;
for (i = 1; i <= n; i++)
{
for (j = 1; j <= n; j++)
{
if (i == 1 || i == n ||
j == 1 || j == n)
System.out.print("*");
else
System.out.print(" ");
}
System.out.println();
}
}
public static void main(String args[])
{
int rows = 8;
print_square(rows);
}
}
Python3
def print_square(n) :
for i in range(1, n+1) :
for j in range(1, n+1) :
if (i ==
1 or i == n or
j == 1 or j == n) :
print("*", end = "")
else :
print(" ", end = "")
print()
rows = 8
print_square(rows)
C#
using System;
class GFG {
static
void print_squaredi(int n)
{
int i, j;
for (i = 1; i <= n; i++)
{
for (j = 1; j <= n; j++)
{
if (i == 1 || i == n ||
j == 1 || j == n ||
i == j || j == (n - i + 1))
Console.Write("*");
else
Console.Write(" ");
}
Console.WriteLine();
}
}
public static void Main()
{
int rows = 8;
print_squaredi(rows);
}
}
PHP
<?php
function print_squaredi($n)
{
$i;
$j;
for($i = 1; $i <= $n; $i++)
{
for
($j = 1; $j <= $n; $j++)
{
if($i == 1 or $i == $n or $j == 1 ||
$j == $n or $i == $j or $j == ($n -
$i + 1))
printf("*");
else
echo " ";
}
echo "\n";
}
}
$rows = 8;
print_squaredi($rows);
?>
Javascript
Javascript
function print_square(int n)
{
var i, j;
for (i = 1; i <= n; i++)
{
for (j = 1; j <= n; j++)
{
if (i == 1 || i == n ||
j == 1 || j == n)
document.write("*");
else
document.write(" ");
}
document.write("\n");
}
}
var rows = 8;
print_square(rows);
Output:
********
** **
* * * *
* ** *
* ** *
* * * *
** **
********
Time Complexity: O(n2), where n represents the given input.
Auxiliary Space: O(1), no extra space
is required, so it is a constant.
An algorithm is given below to explain how to print hollow rectangle star(*) pattern by using for loop. Step 1 − Input number of rows to print at runtime. Step 2 − Use outer for loop for rows from 1 to N. Step 3 − Run an inner loop from 1 to N for columns.
