Php call method in class

I have been trying to figure out how to go about doing this but I am not quite sure how.

Here is an example of what I am trying to do:

class test {
     public newTest(){
          function bigTest(){
               //Big Test Here
          }
          function smallTest(){
               //Small Test Here
          }
     }
     public scoreTest(){
          //Scoring code here;
     }
}

Here is the part I am having problems with, how do I call bigTest()?

tshepang

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asked Nov 12, 2009 at 20:32

3

Try this one:

class test {
     public function newTest(){
          $this->bigTest();
          $this->smallTest();
     }

     private function bigTest(){
          //Big Test Here
     }

     private function smallTest(){
          //Small Test Here
     }

     public function scoreTest(){
          //Scoring code here;
     }
}

$testObject = new test();

$testObject->newTest();

$testObject->scoreTest();

answered Nov 12, 2009 at 20:38

Sergey KuznetsovSergey Kuznetsov

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1

The sample you provided is not valid PHP and has a few issues:

public scoreTest() {
    ...
}

is not a proper function declaration -- you need to declare functions with the 'function' keyword.

The syntax should rather be:

public function scoreTest() {
    ...
}

Second, wrapping the bigTest() and smallTest() functions in public function() {} does not make them private — you should use the private keyword on both of these individually:

class test () {
    public function newTest(){
        $this->bigTest();
        $this->smallTest();
    }

    private function bigTest(){
        //Big Test Here
    }

    private function smallTest(){
           //Small Test Here
    }

    public function scoreTest(){
      //Scoring code here;
    }
}

Also, it is convention to capitalize class names in class declarations ('Test').

Hope that helps.

answered Nov 12, 2009 at 20:48

pjbeardsleypjbeardsley

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class test {
    public newTest(){
        $this->bigTest();
        $this->smallTest();
    }

    private  function bigTest(){
        //Big Test Here
    }

    private function smallTest(){
       //Small Test Here
    }

    public scoreTest(){
      //Scoring code here;
    }
 }

answered Jul 13, 2017 at 11:21

I think you are searching for something like this one.

class test {

    private $str = NULL;

    public function newTest(){

        $this->str .= 'function "newTest" called, ';
        return $this;
    }
    public function bigTest(){

        return $this->str . ' function "bigTest" called,';
    }
    public function smallTest(){

        return $this->str . ' function "smallTest" called,';
    }
    public function scoreTest(){

        return $this->str . ' function "scoreTest" called,';
    }
}

$test = new test;

echo $test->newTest()->bigTest();

bittusarkar

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answered Sep 6, 2015 at 3:54

Ali HasanAli Hasan

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To call any method of an object instantiated from a class (with statement new), you need to "point" to it. From the outside you just use the resource created by the new statement. Inside any object PHP created by new, saves the same resource into the $this variable. So, inside a class you MUST point to the method by $this. In your class, to call smallTest from inside the class, you must tell PHP which of all the objects created by the new statement you want to execute, just write:

$this->smallTest();

Makyen♦

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answered Dec 24, 2014 at 16:58

IngenieroIngeniero

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1

In order to have a "function within a function", if I understand what you're asking, you need PHP 5.3, where you can take advantage of the new Closure feature.

So you could have:

public function newTest() {
   $bigTest = function() {
        //Big Test Here
   }
}

answered Nov 12, 2009 at 20:39

blockheadblockhead

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  class sampleClass
    { 
        public function f1()
        {
           return "f1 run";
        }

        public function f2()
        {
           echo ("f2 run" );
           $result =  $this->f1();
           echo ($result);
        }   

    f2();  

    }

output :

f2 run f1 run

answered Dec 10, 2016 at 13:25

Masoud SiahkaliMasoud Siahkali

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You need to call newTest to make the functions declared inside that method “visible” (see Functions within functions). But that are then just normal functions and no methods.

answered Nov 12, 2009 at 20:35

GumboGumbo

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example 1

class TestClass{
public function __call($name,$arg){
call_user_func($name,$arg);
}
}
class test {
     public function newTest(){

          function bigTest(){
               echo 'Big Test Here';
          }
          function smallTest(){
               echo 'Small Test Here';
          }

$obj=new TestClass;

return $obj;
     }

}
$rentry=new test;
$rentry->newTest()->bigTest();

example2

class test {
     public function newTest($method_name){

          function bigTest(){
               echo 'Big Test Here';
          }
          function smallTest(){
               echo 'Small Test Here';
          }

      if(function_exists( $method_name)){    
call_user_func($method_name);
      }
      else{
          echo 'method not exists';
      }
     }

}
$obj=new test;
$obj->newTest('bigTest')

answered Oct 7, 2013 at 19:20

zloctbzloctb

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1

You can also use self::CONST instead of $this->CONST if you want to call a static variable or function of the current class.

answered Aug 23, 2016 at 17:25

AlexioVayAlexioVay

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