Long number possibilities program in python

Given 3 digits a, b, and c. The task is to find all the possible combinations from these digits.

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How do you calculate how many possible combinations in Python?
How do you find the largest 4 numbers in Python?
How do you find the 3 digit number in Python?
How do you find the largest 5 numbers in Python?

Examples:

Input: [1, 2, 3]
Output:
1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1

Input: [0, 9, 5]
Output:
0 9 5
0 5 9
9 0 5
9 5 0
5 0 9
5 9 0

Method 1: Brute force or Naive approach

The naive approach is to run 3 loops from 0 to 3 and print all the numbers from the list if the indexes are not equal to each other.

Example:

Python3

def comb(L):

for i in range(3):

for j in range(3):

for k in range(3):

if (i!=j and j!=k and i!=k):

print(L[i], L[j], L[k])

comb([1, 2, 3])

Output:

Method 2: Using itertools.permutations()

This method takes a list as an input and returns an object list of tuples that contain all permutation in a list form.

Example:

Python3

from itertools import permutations

comb = permutations([1, 2, 3], 3)

for i in comb:

print(i)

Output:

(1, 2, 3)
(1, 3, 2)
(2, 1, 3)
(2, 3, 1)
(3, 1, 2)
(3, 2, 1)

This is a Python Program to accept three distinct digits and print all possible combinations from the digits.

Problem Description

The program takes three distinct numbers and prints all possible combinations from the digits.

Problem Solution

1. Take in the first, second and third number and store it in separate variables.
2. Then append all the three numbers to the list.
3. Use three for loops and print the digits in the list if none of their indexes are equal to each other.
4. Exit.

Program/Source Code

Here is the source code of the Python Program to accept three distinct digits and prints all possible combinations from the digits. The program output is also shown below.

 
a=int(input("Enter first number:"))
b=int(input("Enter second number:"))
c=int(input("Enter third number:"))
d=[]
d.append(a)
d.append(b)
d.append(c)
for i in range(0,3):
    for j in range(0,3):
        for k in range(0,3):
            if(i!=j&j!=k&k!=i):
                print(d[i],d[j],d[k])

Program Explanation

1. User must enter the first, second and third number.
2. All the elements are appending into a list for the ease of comparison.
3. The for loops range from 0-2 which are basically the indexes of the three elements in the list.
4. If none of the indexes are equal to each other, the element associated with the particular element in the list is printed.

Runtime Test Cases

 
Case 1:
Enter first number:1
Enter second number:2
Enter third number:3
1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1
 
Case 2:
Enter first number:5
Enter second number:7
Enter third number:3
5 7 3
5 3 7
7 5 3
7 3 5
3 5 7
3 7 5

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How do you calculate how many possible combinations in Python?

To calculate combinations in Python, use the itertools. combinations() method. The itertools. combinations() method takes an iterator as an argument and returns all the possible combinations of elements in the iterator.

How do you find the largest 4 numbers in Python?

You can use Python's built-in max() function, which returns the maximum value of a sequence. That would look something like this: maximum = max(num1, num2, num3, num4) if num1 == maximum: ...

How do you find the 3 digit number in Python?

To format a number to 3 digits:.

Use the str() class to convert the number to a string..

Use the str. zfill() method to format the number to 3 digits..

The str. zfill() method will format the number to 3 digits by left-filling it with 0 digits..

How do you find the largest 5 numbers in Python?

In Python, there is a built-in function max() you can use to find the largest number in a list. To use it, call the max() on a list of numbers. It then returns the greatest number in that list.