How do you write odd numbers in python?

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Method: Using pass
Method: Using recursion
Method: Using enumerate function
How do you do odd numbers in Python?
How do you print odd digits of a number in Python?
How do you code an odd number?
How do you assign odd and even numbers in Python?

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Given a list of numbers, write a Python program to print all odd numbers in given list. Example:

Input: list1 = [2, 7, 5, 64, 14]
Output: [7, 5]

Input: list2 = [12, 14, 95, 3, 73]
Output: [95, 3, 73]

Using for loop : Iterate each element in the list using for loop and check if num % 2 != 0. If the condition satisfies, then only print the number.

Python3

list1 = [10, 21, 4, 45, 66, 93]

for num in list1:

if num % 2 != 0:

print(num, end = " ")

Output:

21 45 93

Using while loop :

Python3

list1 = [10, 21, 4, 45, 66, 93]

i = 0

while(i < len(list1)):

if list1[i] % 2 != 0:

print(list1[i], end = " ")

i += 1

Output:

21 45 93

Using list comprehension :

Python3

list1 = [10, 21, 4, 45, 66, 93]

only_odd = [num for num in list1 if num % 2 == 1]

print(only_odd)

Output:

21 45 93

Using lambda expressions :

Python3

list1 = [10, 21, 4, 45, 66, 93, 11]

odd_nos = list(filter(lambda x: (x % 2 != 0), list1))

print("Odd numbers in the list: ", odd_nos)

Output:

Odd numbers in the list:  [21, 45, 93, 11]

Method: Using pass

Python3

lst=[10,21,4,45,66,93,11]

for i in lst:

if i%2==0:

pass

else:

print(i,end=" ")

Method: Using recursion

Python3

def oddnumbers(list, n=0):

if n==len(list):

exit()

if list[n]%2!=0:

print(list[n], end=" ")

oddnumbers(list, n+1)

list1 = [10, 21, 4, 45, 66, 93,11]

print("odd numbers in the list:", end=" ")

oddnumbers(list1)

Output

odd numbers in the list: 21 45 93 11

Method: Using enumerate function

Python3

list1 = [2, 7, 5, 64, 14]

for a,i in enumerate(list1):

if i%2!=0:

print(i,end=" ")

Auxiliary Space: O(1)

How do you do odd numbers in Python?

Also, if…else statements will be used. The required code is provided below. num = int (input (“Enter any number to test whether it is odd or even: “) if (num % 2) == 0: print (“The number is even”) else: print (“The provided number is odd”) Output: Enter any number to test whether it is odd or even: 887 887 is odd.

How do you print odd digits of a number in Python?

num = int(input("Enter a number: ")) mod = num % 2 if mod > 0: print("This is an odd number. ") else: print("This is an even number. ")

How do you code an odd number?

Program to Check Even or Odd If the number is perfectly divisible by 2 , test expression number%2 == 0 evaluates to 1 (true). This means the number is even. However, if the test expression evaluates to 0 (false), the number is odd.

How do you assign odd and even numbers in Python?

Step 1 : create a user input list. Step 2 : take two empty list one for odd and another for even. Step 3 : then traverse each element in the main list. Step 4 : every element is divided by 2, if remainder is 0 then it's even number and add to the even list, otherwise its odd number and add to the odd list.