I need to allow users on my website to delete their images off the server after they have uploaded them if they no longer want them. I was previously using the unlink function in PHP but have since been told that this can be quite risky and a security issue. (Previous code below:)
if(unlink($path.'image1.jpg')){ // deleted }Instead i now want to simply move the file into a different folder. This must be able to be done a long time after they have first uploaded the file so any time they log into their account. If i have the main folder which stores the users image(s):
user/and then within that a folder called del which is the destination to put their unwanted images:
user/del/Is there a command to move a file into a different folder? So that say:
user/image1.jpgmoves to/becomes
user/del/image1.jpgasked Oct 2, 2013 at 14:28
The rename function does this
docs rename
rename('image1.jpg', 'del/image1.jpg');
If you want to keep the existing file on the same place you should use copy
docs copy
copy('image1.jpg', 'del/image1.jpg');
If you want to move an uploaded file use the move_uploaded_file, although this is almost the same as rename this function also checks that the given file is a file that was uploaded via the POST, this prevents for example that a local file is moved
docs move_uploaded_file
$uploads_dir = '/uploads'; foreach ($_FILES["pictures"]["error"] as $key => $error) { if ($error == UPLOAD_ERR_OK) { $tmp_name = $_FILES["pictures"]["tmp_name"][$key]; $name = $_FILES["pictures"]["name"][$key]; move_uploaded_file($tmp_name, "$uploads_dir/$name"); } }code snipet from docs
answered Oct 2, 2013 at 14:33
MKroedersMKroeders
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Use the rename() function.
rename("user/image1.jpg", "user/del/image1.jpg");answered Oct 2, 2013 at 14:32
Ben FortuneBen Fortune
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If you want to move the file in new path with keep original file name. use this:
$source_file = 'foo/image.jpg'; $destination_path = 'bar/'; rename($source_file, $destination_path . pathinfo($source_file, PATHINFO_BASENAME));answered Jan 24, 2018 at 16:38
Nabi K.A.Z.Nabi K.A.Z.
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I using shell read all data file then assign to array. Then i move file in top position.
i=0 for file in /home/*.gz; do $file arr[i]=$file i=$((i+1)) done mv -f "${arr[0]}" /var/www/html/answered Mar 22, 2019 at 9:52
1
Some solution is first to copy() the file (as mentioned above) and when the destination file exists - unlink() file from previous localization. Additionally you can validate the MD5 checksum before unlinking to be sure
answered Nov 6, 2018 at 13:25
quardasquardas
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Create a function to move it:
function move_file($file, $to){ $path_parts = pathinfo($file); $newplace = "$to/{$path_parts['basename']}"; if(rename($file, $newplace)) return $newplace; return null; }answered Mar 19, 2019 at 16:49
MarceloMarcelo
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use copy() and unlink() function
$moveFile="path/filename"; if (copy($csvFile,$moveFile)) { unlink($csvFile); }answered Mar 20, 2019 at 10:00
Use file this code
function move_file($path,$to){ if(copy($path, $to)){ unlink($path); return true; } else { return false; } }answered Jan 17, 2021 at 18:03
function xmove($src,$dst) { if(is_dir($src)===true) { $dir=opendir($src); while (($file = readdir($dir)) !== false) { if ($file === '.' || $file === '..') { continue; } if (is_dir($src."/".$file) === true) { if (is_dir("$dst/$file") === false) { mkdir("$dst/$file"); } //echo basename("$file")."<br>"; xmove($src."/".$file,$dst."/".$file); } else { copy("$src/$file", "$dst/$file"); unlink("$src/$file"); } } closedir($dir); rmdir($src); return true; }else return false; }
answered Nov 1, 2021 at 17:29
1
shell_exec('mv filename dest_filename');
answered Sep 21, 2018 at 6:28
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