Write a python program to print even numbers from given range using while loop

Use a while loop with if statement condition i % 2 == 0 then only print the first 10 even numbers in Python.

Simple example code print even numbers of user input value using a while loop in Python. You can use list objects to store value, here we are printing the value using the end keyword.

x = int(input("Enter a number: "))
i = 1

while i <= x:
    if i % 2 == 0:
        print(i, end=" ")
    i = i + 1

Output:

Without if statement

num = 2

while num <= 20:
    print(num)
    num = num + 2

Output:

2
4
6
8
10
12
14
16
18
20

Do comment if you have any doubts or suggestions on this Python even number topic.

Note: IDE: PyCharm 2021.3.3 (Community Edition)

Windows 10

Python 3.10.1

All Python Examples are in Python 3, so Maybe its different from python 2 or upgraded versions.

Degree in Computer Science and Engineer: App Developer and has multiple Programming languages experience. Enthusiasm for technology & like learning technical.

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Given starting and end points, write a Python program to print all even numbers in that given range. 

Example:

Input: start = 4, end = 15
Output: 4, 6, 8, 10, 12, 14

Input: start = 8, end = 11
Output: 8, 10

Example #1: Print all even numbers from given list using for loop Define start and end limit of range. Iterate from start till the range in the list using for loop and check if num % 2 == 0. If the condition satisfies, then only print the number. 

Python3

for num in range(4,15,2):

    print(num)

Output:

4 6 8 10 12 14 

  Example #2: Taking range limit from user input 

Python3

start = int(input("Enter the start of range: "))

end = int(input("Enter the end of range: "))

for num in range(start, end + 1):

    if num % 2 == 0:

        print(num, end=" ")

Output:

Enter the start of range: 4
Enter the end of range: 10
4 6 8 10 

Example#3 Taking range limit user input and uses skip sequence number in range function which generates the all-even number. 

Python3

start = int(input("Enter the start of range: "))

end = int(input("Enter the end of range: "))

start = start+1 if start&1 else start

[ print( x ) for x in range(start, end + 1, 2)]

Output:

Enter the start of range: 4
Enter the end of range: 10
4 6 8 10 

Method: Using recursion 

Python3

def even(num1,num2):

    if num1>num2:

        return

    print(num1,end=" ")

    return even(num1+2,num2)

num1=4;num2=15

even(num1,num2)

Method: Using the lambda function 

Python3

a=4;b=15

li=[]

for i in range(a,b+1):

    li.append(i)

even_num = list(filter(lambda x: (x%2==0),li)) 

print(even_num)

Output

[4, 6, 8, 10, 12, 14]

Method: Using list comprehension 

Python3

x=[i for i in range(4,15+1) if i%2==0]

print(*x)

Method: Using enumerate function 

Python3

a=4;b=15;l=[]

for i in range(a,b+1):

  l.append(i)

print([a for j,a in enumerate(l) if a%2==0])

Output

[4, 6, 8, 10, 12, 14]

Method: Using pass 

Python3

a=4;b=15

for i in range(a,b+1):

  if i%2!=0:

    pass

  else:

    print(i,end=" ")

Method: Using Numpy.Array

Python3

import numpy as np

a=4;b=15

li= np.array(range(a, b+1))

even_num = li[li%2==0];

print(even_num)

Output:

[ 4  6  8 10 12 14]