Suppose we have three strings text, w1, and w2. The text is a sentence with different words. We have to find the smallest distance between any two occurrences of w1 and w2 in the text, the distance is measured in number of words in between them. If either w1 or w2 is not present in text, return -1.
So, if the input is like text = "joy happy power happy joy joy power happy limit" w1 = "power" w2 = "limit", then the output will be 1, as there is only one word "happy" in between the power and limit.
To solve this, we will follow these steps −
index1 := null, index2 := null
distance := 999999
for each index idx and word w in text, do
if w is same as w1, then
if index2 is not null, then
distance := minimum of distance and (|idx - index2| - 1)
index1 := idx
if w is same as w2, then
if index1 is not null, then
distance := minimum of distance and (|idx - index1| - 1)
index2 := idx
if index1 is not null and index2 is not null, then
return distance
return -1
Example
Let us see the following implementation to get better understanding
def solve(text, w1, w2): index1 = None index2 = None distance = 2000000 for idx, word in enumerate(text.split(" ")): if word == w1: if index2 is not None: distance = min(distance, abs(idx - index2) - 1) index1 = idx if word == w2: if index1 is not None: distance = min(distance, abs(idx - index1) - 1) index2 = idx if index1 is not None and index2 is not None: return distance return -1 text = "joy happy power happy joy joy power happy limit" w1 = "power" w2 = "limit" print(solve(text, w1, w2))Input
"joy happy power happy joy joy power happy limit", "power", "limit"Output
1
Updated on 12-Oct-2021 11:18:51
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Suppose we have two strings, word0, and word1 and a text. We have to find the smallest distance between any two occurrences of word0 and word1 in the given text. Here the distance is measured in number of words. If they are not present in the text then return -1.
So, if the input is like text = "cat dog abcd dog cat cat abcd dog wxyz", word0 = "abcd", word1 = "wxyz", then the output will be 1, as there is one word "dog" between "abcd" and "wxyz"
To solve this, we will follow these steps −
- word_list := a list of words from text
- ans := size of word_list
- L := null
- for R in range 0 to size of word_list - 1, do
- if word_list[R] is word0 or word_list[R] is word1, then
- if L is not null and word_list[R] is not word_list[L], then
- ans := minimum of ans and R - L - 1
- L := R
- if L is not null and word_list[R] is not word_list[L], then
- if word_list[R] is word0 or word_list[R] is word1, then
- return -1 if ans is same as size of word_list otherwise ans
Let us see the following implementation to get better understanding −
Example
Live Demo
class Solution: def solve(self, text, word0, word1): word_list = text.split() ans = len(word_list) L = None for R in range(len(word_list)): if word_list[R] == word0 or word_list[R] == word1: if L is not None and word_list[R] != word_list[L]: ans = min(ans, R - L - 1) L = R return -1 if ans == len(word_list) else ans ob = Solution() text = "cat dog abcd dog cat cat abcd dog wxyz" word0 = "abcd" word1 = "wxyz" print(ob.solve(text, word0, word1))Input
"cat dog abcd dog cat cat abcd dog wxyz", "abcd", "wxyz"Output
1
Updated on 22-Sep-2020 11:25:39
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