I already asked similar question about this but that only for list of number from 0 to 15. i thought what about trying to convert numbers from 0 to more than 15.Here is what I wrote so far
def base_convert(i, b): result = [] for i in range(20): while i > 0: result.insert(0, i % b) i = i // b return result print(base_convert(i,4))but I got error saying that name 'i' is not defined. Did I missed something here? Or maybe I wrote a wrong code. Thank you for the answer.
asked Jan 14, 2016 at 17:54
6
Three problems:
- You haven't defined i when you call the function as mentionned by Morgan
- i is an input arg so you should not override it in the function before using it.
- You do not need the for loop.
It should look like the following with the test for 9
def base_convert(i, b): result = [] while i > 0: result.insert(0, i % b) i = i // b return result print(base_convert(9,4)answered Jan 14, 2016 at 18:08
innoSPGinnoSPG
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This post deals with the methods to inter-convert decimal to any base system number into any base depending on the user input in Python.
Prerequisites: Basics of python looping constructs
Decimal to Any Base – The Method
The basic algorithm for this conversion is to repeatedly divide (integer division) the given decimal number by the target base value until the decimal number becomes 0. The remainder in each case forms the digits of the number in the new base system, however, in the reverse order.
An Upper Limit
The algorithm, in general, will work for any base, but we need digits/characters to represent that many numbers of a base system. For simplicity, we limit ourselves to base 36 i.e 10 numbers + 26 alphabets. (We can differentiate lower and upper case, but we intend to focus on the algorithm here!). It will be clear after the implementation that the method has to work for any base.
Decimal to Any Base – Python Implementation
Consider the following program,
def dec_to_base(num,base): #Maximum base - 36 base_num = "" while num>0: dig = int(num%base) if dig<10: base_num += str(dig) else: base_num += chr(ord('A')+dig-10) #Using uppercase letters num //= base base_num = base_num[::-1] #To reverse the string return base_numNotice the if condition used to check if digits 0-9 are enough to accommodate all digits in the base. Otherwise, we are assigning a suitable alphabet for the digit.
ord(<character>) – Built-in function that returns the ASCII value of character
chr(<integer>) – Built-in function that returns the character with ASCII value – <integer>
The last line is used as a string reversal operation. It basically produces a slice of string from beginning to end ( signified by first two empty arguments) by traversing from the end to start (signified by -1).
This a sample output, converting to base 28
Hence we are able to convert a decimal number into any base required.
Some Built-In Base Conversion Methods
Python provides some built-in base conversion methods for binary, octal and hexadecimal numbers.
The usage is very simple:
bin(<decimal_integer>) – Returns a string, which is binary representation of decimal number
oct(<decimal_integer>) – Returns a string, which is octal representation of decimal number
hex(<decimal_integer>) – Returns a string, which is hecadecimal representation of decimal number
Any Base to Decimal
Python also provides easy conversion from any base to decimal. This done by simply passing a string that has the other base representation of a decimal number and the base value as the second argument. It returns the decimal number!
print int("1123",5) #Prints string given in base-5 in decimalThe output is: 163
Algorithm and Implementation for Any Base to Decimal
The logic is very simple. We just have to multiply each digit at a position with the base value raised to the place value(starting from 0 from right-side). That is how a base system is defined, in fact.
For instance, if 1011 is a binary number, the decimal equivalent is
(1 x 2^0) + (1 x 2^1) + (0 x 2^2) + (1 x 2^3) = 11
The following program illustrates the same,
def base_to_dec(num_str,base): num_str = num_str[::-1] num = 0 for k in range(len(num_str)): dig = num_str[k] if dig.isdigit(): dig = int(dig) else: #Assuming its either number or alphabet only dig = ord(dig.upper())-ord('A')+10 num += dig*(base**k) return numBelow is a sample output for the same value converted in the previous output
Feel free to leave behind any sort of feedback, suggestion, doubts below.