Php date minus 6 months

I have date in this format (YYYYMM):

201201  // Gen, 2012
201202  // Feb, 2012
201203  // ecc

Let's say from 201203 I want to subtract 4 months. I can't do 201203 - 4 because it's = 201199

201203 - 4 should output 201111 (Nov, 2011)

Maybe i should convert my string to a date and then pass it to strtotime with -4 month?

Any suggest ?

asked May 17, 2012 at 10:22

4

You can use strtotime in PHP:

$date = strtotime('2012-05-01 -4 months');

This article will help you.

answered May 17, 2012 at 10:25

pearcodingpearcoding

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strtotime() can do it but you will need to add a day of the month for it to parse the date:

$input = '201203';

$input .= '01';

$date = strtotime($input .' -4 months');

echo date('Ym', $date);

Outputs Nov 2011:

201111

answered May 17, 2012 at 10:30

MrCodeMrCode

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0

Apart from the strtotime versions, since PHP 5.3 you can also use DateTime and DateInterval:

$date = DateTime::createFromFormat("Ym", "201201");
$interval = new DateInterval("P4M"); // 4 months
$fourMonthsEarlier = $date->sub($interval);
echo $fourMonthsEarlier->format("Ym");

answered May 17, 2012 at 10:35

JonJon

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Final_date = Currentdate - 4 months

<?php
$current_date = date("Y-m-d");

$final_date = date("Y-m-d", strtotime($current_date." -4 months"));

echo $final_date;

answered Sep 4, 2018 at 11:36

Kiran ReddyKiran Reddy

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for EX $da=2014-04-01

if u want to minus 6 months use this..

$date = strtotime($da .' -4 months');
$final=date('Y-m-d', $date);

echo $final;

answered Apr 17, 2014 at 8:10

You can use strtotime to convert the string to a UNIX timestamp, which is in seconds. time() will give you the current UNIX timestamp. Subtract them to get how old the date is in seconds, and divide by 60*60*24 to get it in days

answered May 17, 2012 at 10:25

NorseNorse

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Previous code not working:

$da='2014-08-29';
$date = strtotime($da .' -6 months');
$final=date('Y-m-d', $date);
echo $final;
$date = strtotime($da .' -7 months');
$final=date('Y-m-d', $date);
echo $final;

February is missing!

answered Aug 29, 2014 at 12:14

1

$date = '2016-09-01 00:00:00.000000';

$date2 = date("Y-m-d H:i:s.u", strtotime($date." -4 months"));

echo $date2; 

on run this code you will get 2016-05-01 00:00:00.000000

answered Sep 15, 2016 at 12:36