How do i make a list of 100 numbers in python?

Create a list of 100 integers whose value and index are the same, e.g.

mylist[0] = 0, mylist[1] = 1, mylist[2] = 2, ...

Here is my code.

x_list=[] def list_append(x_list): for i in 100: x_list.append(i) return(list_append()) print(x_list)

Veedrac

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asked Sep 26, 2013 at 3:49

2

Since nobody else realised you're using Python 3, I'll point out that you should be doing list(range(100)) to get the wanted behaviour.

answered Sep 26, 2013 at 4:22

VeedracVeedrac

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Use range() for generating such a list

>>> range(10) [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] >>> range(10)[5] 5

answered Sep 26, 2013 at 3:50

for i in 100 doesn't do what you think it does. int objects are not iterable, so this won't work. The for-loop tries to iterate through the object given.

If you want to get a list of numbers between 0-100, use range():

for i in range(100): dostuff()

The answer to your question is pretty much range(100) anyway:

>>> range(100)[0] 0 >>> range(100)[64] 64

answered Sep 26, 2013 at 3:50

TerryATerryA

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You can use range(100), but it seems that you are probably looking to make the list from scratch, so there you can use while:

x_list=[] i = 0 while i<100: x_list.append(i) i += 1

Or you could do this recursively:

def list_append(i, L): L.append(i) if i==99: return L list_append(i+1, L) x_list = [] list_append(0, x_list) print x_list

answered Sep 26, 2013 at 3:52

tom10tom10

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1

Also can use List Comprehensions, like

[x for x in range(100)]

answered Apr 30, 2018 at 12:58

If you want to import numpy you could do something like this:

import numpy as np x_list = np.arange(0, 100).tolist()

Should work in python2.7 and python3.x

answered Apr 28, 2018 at 18:07

import random data1=[] def f(x): return(random.randrange(0,1000)) for x in range (0,100): data1.append(f(x)) data1

double-beep

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answered Apr 29, 2020 at 2:47

2

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