Get only integer part in php

Given, say, 1.25 - how do I get "1" and ."25" parts of this number?

I need to check if the decimal part is .0, .25, .5, or .75.

alex

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asked Jul 8, 2011 at 2:31

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$n = 1.25; $whole = floor($n); // 1 $fraction = $n - $whole; // .25

Then compare against 1/4, 1/2, 3/4, etc.

In cases of negative numbers, use this:

function NumberBreakdown($number, $returnUnsigned = false) { $negative = 1; if ($number < 0) { $negative = -1; $number *= -1; } if ($returnUnsigned){ return array( floor($number), ($number - floor($number)) ); } return array( floor($number) * $negative, ($number - floor($number)) * $negative ); }

The $returnUnsigned stops it from making -1.25 in to -1 & -0.25

seanbreeden

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answered Jul 8, 2011 at 2:33

Brad ChristieBrad Christie

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This code will split it up for you:

list($whole, $decimal) = explode('.', $your_number);

where $whole is the whole number and $decimal will have the digits after the decimal point.

answered Jul 8, 2011 at 2:33

5

The floor() method doesn't work for negative numbers. This works every time:

$num = 5.7; $whole = (int) $num; // 5 $frac = $num - $whole; // .7

...also works for negatives (same code, different number):

$num = -5.7; $whole = (int) $num; // -5 $frac = $num - $whole; // -.7

evilReiko

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answered Feb 6, 2016 at 13:08

thedudethedude

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Just to be different :)

list($whole, $decimal) = sscanf(1.5, '%d.%d');

CodePad.

As an added benefit, it will only split where both sides consist of digits.

answered Jul 8, 2011 at 2:43

alexalex

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a short way (use floor and fmod)

$var = "1.25"; $whole = floor($var); // 1 $decimal = fmod($var, 1); //0.25

then compare $decimal to 0, .25, .5, or .75

answered Nov 6, 2015 at 8:21

mpalenciampalencia

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Cast it as an int and subtract

$integer = (int)$your_number; $decimal = $your_number - $integer;

Or just to get the decimal for comparison

$decimal = $your_number - (int)$your_number

answered Dec 5, 2014 at 17:28

DomDom

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There's a fmod function too, that can be used : fmod($my_var, 1) will return the same result, but sometime with a small round error.

answered May 9, 2013 at 19:11

ip512ip512

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PHP 5.4+

$n = 12.343; intval($n); // 12 explode('.', number_format($n, 1))[1]; // 3 explode('.', number_format($n, 2))[1]; // 34 explode('.', number_format($n, 3))[1]; // 343 explode('.', number_format($n, 4))[1]; // 3430

answered Sep 14, 2017 at 11:51

This is the way which I use:

$float = 4.3; $dec = ltrim(($float - floor($float)),"0."); // result .3

alex

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answered Mar 14, 2014 at 14:03

Serdar D.Serdar D.

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Just a new simple solution, for those of you who want to get the Integer part and Decimal part splitted as two integer separated values:

5.25 -> Int part: 5; Decimal part: 25

$num = 5.25; $int_part = intval($num); $dec_part = $num * 100 % 100;

This way is not involving string based functions, and is preventing accuracy problems which may arise in other math operations (such as having 0.49999999999999 instead of 0.5).

Haven't tested thoroughly with extreme values, but it works fine for me for price calculations.

But, watch out! Now from -5.25 you get: Integer part: -5; Decimal part: -25

In case you want to get always positive numbers, simply add abs() before the calculations:

$num = -5.25; $num = abs($num); $int_part = intval($num); $dec_part = $num * 100 % 100;

Finally, bonus snippet for printing prices with 2 decimals:

$message = sprintf("Your price: %d.%02d Eur", $int_part, $dec_part);

...so that you avoid getting 5.5 instead of 5.05. ;)

answered Dec 4, 2020 at 8:57

MarcMMarcM

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Brad Christie's method is essentially correct but it can be written more concisely.

function extractFraction ($value) { $fraction = $value - floor ($value); if ($value < 0) { $fraction *= -1; } return $fraction; }

This is equivalent to his method but shorter and hopefully easier to understand as a result.

answered Oct 4, 2015 at 9:40

GordonMGordonM

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I was having a hard time finding a way to actually separate the dollar amount and the amount after the decimal. I think I figured it out mostly and thought to share if any of yall were having trouble

So basically...

if price is 1234.44... whole would be 1234 and decimal would be 44 or

if price is 1234.01... whole would be 1234 and decimal would be 01 or

if price is 1234.10... whole would be 1234 and decimal would be 10

and so forth

$price = 1234.44; $whole = intval($price); // 1234 $decimal1 = $price - $whole; // 0.44000000000005 uh oh! that's why it needs... (see next line) $decimal2 = round($decimal1, 2); // 0.44 this will round off the excess numbers $decimal = substr($decimal2, 2); // 44 this removed the first 2 characters if ($decimal == 1) { $decimal = 10; } // Michel's warning is correct... if ($decimal == 2) { $decimal = 20; } // if the price is 1234.10... the decimal will be 1... if ($decimal == 3) { $decimal = 30; } // so make sure to add these rules too if ($decimal == 4) { $decimal = 40; } if ($decimal == 5) { $decimal = 50; } if ($decimal == 6) { $decimal = 60; } if ($decimal == 7) { $decimal = 70; } if ($decimal == 8) { $decimal = 80; } if ($decimal == 9) { $decimal = 90; } echo 'The dollar amount is ' . $whole . ' and the decimal amount is ' . $decimal;

answered Oct 6, 2017 at 22:30

$x = 1.24 $result = $x - floor($x); echo $result; // .24

answered Mar 27, 2018 at 22:40

If you can count on it always having 2 decimal places, you can just use a string operation:

$decimal = 1.25; substr($decimal,-2); // returns "25" as a string

No idea of performance but for my simple case this was much better...

answered Mar 24, 2019 at 1:51

Ben BarrethBen Barreth

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To prevent the extra float decimal (i.e. 50.85 - 50 give 0.850000000852), in my case I just need 2 decimals for money cents.

$n = 50.85; $whole = intval($n); $fraction = $n * 100 % 100;

answered Sep 1, 2016 at 8:53

fbaudetfbaudet

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Try it this way... it's easier like this

$var = "0.98"; $decimal = strrchr($var,"."); $whole_no = $var-$decimal; echo $whole_no; echo str_replace(".", "", $decimal);

answered Dec 18, 2020 at 14:04

You could also use something like this:

preg_match("/([0-9]+)\.([0-9]+)/", $number, $matches);

answered Apr 27, 2021 at 18:45

Inc33Inc33

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If you want the two halves to be explicitly type cast, then sscanf() is a great call.

Code: (Demo)

var_dump(sscanf(1.25, '%d%f'));

Output:

array(2) { [0]=> int(1) [1]=> float(0.25) }

Or you can assign the two variables individually:

sscanf(1.25, '%d%f', $int, $float); var_dump($int); var_dump($float);

Casting the decimal portion as a float is particularly useful when, say, converting decimal expression of hours to hours and minutes. (Demo)

$decimalTimes = [ 6, 7.2, 8.78, ]; foreach ($decimalTimes as $decimalTime) { sscanf($decimalTime, '%d%f', $hours, $minutes); printf('%dh%02dm', $hours, round($minutes * 60)); echo "\n"; }

Output:

6h00m 7h22m 8h47m // if round() was not used, this would be 8h46m

answered Sep 3, 2021 at 3:28

mickmackusamickmackusa

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Not seen a simple modulus here...

$number = 1.25; $wholeAsFloat = floor($number); // 1.00 $wholeAsInt = intval($number); // 1 $decimal = $number % 1; // 0.25

In this case getting both $wholeAs? and $decimal don't depend on the other. (You can just take 1 of the 3 outputs independently.) I've shown $wholeAsFloat and $wholeAsInt because floor() returns a float type number even though the number it returns will always be whole. (This is important if you're passing the result into a type-hinted function parameter.)

I wanted this to split a floating point number of hours/minutes, e.g. 96.25, into hours and minutes separately for a DateInterval instance as 96 hours 15 minutes. I did this as follows:

$interval = new \DateInterval(sprintf("PT%dH%dM", intval($hours), (($hours % 1) * 60)));

I didn't care about seconds in my case.

answered Feb 5, 2019 at 16:36

AdambeanAdambean

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val = -3.1234 fraction = abs(val - as.integer(val) )

Bhargav Rao

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answered Jan 10, 2016 at 16:55

1

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