Get first date of month python

I'm trying to find the first day of the month in python with one condition: if my current date passed the 25th of the month, then the first date variable will hold the first date of the next month instead of the current month. I'm doing the following:

import datetime 
todayDate = datetime.date.today()
if (todayDate - todayDate.replace(day=1)).days > 25:
    x= todayDate + datetime.timedelta(30)
    x.replace(day=1)
    print x
else:
    print todayDate.replace(day=1)

is there a cleaner way for doing this?

Mel

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asked May 23, 2016 at 16:42

2

Can be done on the same line using date.replace:

from datetime import datetime

datetime.today().replace(day=1)

cglacet

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answered Jul 23, 2017 at 15:40

5

This is a pithy solution.

import datetime 

todayDate = datetime.date.today()
if todayDate.day > 25:
    todayDate += datetime.timedelta(7)
print todayDate.replace(day=1)

One thing to note with the original code example is that using timedelta(30) will cause trouble if you are testing the last day of January. That is why I am using a 7-day delta.

answered May 23, 2016 at 17:05

andrewandrew

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1

Use dateutil.

from datetime import date
from dateutil.relativedelta import relativedelta

today = date.today()
first_day = today.replace(day=1)
if today.day > 25:
    print(first_day + relativedelta(months=1))
else:
    print(first_day)

answered May 23, 2016 at 16:55

lampslavelampslave

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1

from datetime import datetime

date_today = datetime.now()
month_first_day = date_today.replace(day=1, hour=0, minute=0, second=0, microsecond=0)
print(month_first_day)

answered Dec 13, 2018 at 7:24

Balaji.J.BBalaji.J.B

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1

Use arrow.

import arrow
arrow.utcnow().span('month')[0]

answered Jul 17, 2018 at 10:03

ImPerat0R_ImPerat0R_

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This could be an alternative to Gustavo Eduardo Belduma's answer:

import datetime 
first_day_of_the_month = datetime.date.today().replace(day=1)

answered Apr 9, 2020 at 7:54

tjurkantjurkan

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1

Yes, first set a datetime to the start of the current month.

Second test if current date day > 25 and get a true/false on that. If True then add add one month to the start of month datetime object. If false then use the datetime object with the value set to the beginning of the month.

import datetime 
from dateutil.relativedelta import relativedelta

todayDate = datetime.date.today()
resultDate = todayDate.replace(day=1)

if ((todayDate - resultDate).days > 25):
    resultDate = resultDate + relativedelta(months=1)

print resultDate

answered May 23, 2016 at 16:56

mba12mba12

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The arrow module will steer you around and away from subtle mistakes, and it's easier to use that older products.

import arrow

def cleanWay(oneDate):
    if currentDate.date().day > 25:
        return currentDate.replace(months=+1,day=1)
    else:
        return currentDate.replace(day=1)


currentDate = arrow.get('25-Feb-2017', 'DD-MMM-YYYY')
print (currentDate.format('DD-MMM-YYYY'), cleanWay(currentDate).format('DD-MMM-YYYY'))

currentDate = arrow.get('28-Feb-2017', 'DD-MMM-YYYY')
print (currentDate.format('DD-MMM-YYYY'), cleanWay(currentDate).format('DD-MMM-YYYY'))

In this case there is no need for you to consider the varying lengths of months, for instance. Here's the output from this script.

25-Feb-2017 01-Feb-2017
28-Feb-2017 01-Mar-2017

answered Feb 22, 2017 at 14:41

Bill BellBill Bell

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1

I found a clean way to do this is to create a datetime object using the month and year attributes of todayDate, with days set to 1 i.e.

import datetime 
todayDate = datetime.date.today()

firstOfMon = datetime.date(todayDate.year, todayDate.month, 1)

answered Sep 24, 2021 at 11:05

You can use dateutil.rrule:

In [1]: from dateutil.rrule import *

In [2]: rrule(DAILY, bymonthday=1)[0].date()
Out[2]: datetime.date(2018, 10, 1)

In [3]: rrule(DAILY, bymonthday=1)[1].date()
Out[3]: datetime.date(2018, 11, 1)

answered Sep 21, 2018 at 8:06

dtatarkindtatarkin

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One-liner:

from datetime import datetime, timedelta
last_month=(datetime.now().replace(day=1) - timedelta(days=1)).replace(day=1)

answered Dec 7, 2021 at 10:32

My solution to find the first and last day of the current month:

def find_current_month_last_day(today: datetime) -> datetime:
    if today.month == 2:
        return today.replace(day=28)

    if today.month in [4, 6, 9, 11]:
        return today.replace(day=30)

    return today.replace(day=31)


def current_month_first_and_last_days() -> tuple:
    today = datetime.now().replace(hour=0, minute=0, second=0, microsecond=0)
    first_date = today.replace(day=1)
    last_date = find_current_month_last_day(today)
    return first_date, last_date

answered Oct 22, 2019 at 10:17

mhyousefimhyousefi

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First day of next month:

from datetime import datetime

class SomeClassName(models.Model):
    if datetime.now().month == 12:
        new_start_month = 1
    else:
        new_start_month = datetime.now().month + 1

Then we replace the month and the day

    start_date = models.DateField(default=datetime.today().replace(month=new_start_month, day=1, hour=0, minute=0, second=0, microsecond=0))

answered Jul 22, 2020 at 15:40

Inspired by Jouberto's and @akx's answers (elsewhere), oneliners without any dependencies:

now = datetime.datetime.now(tz=ZoneInfo("UTC"))
this_month = now.replace(day=1, hour=0, minute=0, second=0, microsecond=0)
next_month = (this_month.replace(day=28) + datetime.timedelta(days=4)).replace(day=1)
last_month = (this_month.replace(day=1) - datetime.timedelta(days=1)).replace(day=1)

answered Sep 5 at 12:53

Aapo RistaAapo Rista

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