Can i replace multiple characters in a string python?

Replacing two characters

I timed all the methods in the current answers along with one extra.

With an input string of abc&def#ghi and replacing & -> \& and # -> \#, the fastest way was to chain together the replacements like this: text.replace('&', '\&').replace('#', '\#').

Timings for each function:

  • a) 1000000 loops, best of 3: 1.47 μs per loop
  • b) 1000000 loops, best of 3: 1.51 μs per loop
  • c) 100000 loops, best of 3: 12.3 μs per loop
  • d) 100000 loops, best of 3: 12 μs per loop
  • e) 100000 loops, best of 3: 3.27 μs per loop
  • f) 1000000 loops, best of 3: 0.817 μs per loop
  • g) 100000 loops, best of 3: 3.64 μs per loop
  • h) 1000000 loops, best of 3: 0.927 μs per loop
  • i) 1000000 loops, best of 3: 0.814 μs per loop

Here are the functions:

def a(text):
    chars = "&#"
    for c in chars:
        text = text.replace(c, "\\" + c)


def b(text):
    for ch in ['&','#']:
        if ch in text:
            text = text.replace(ch,"\\"+ch)


import re
def c(text):
    rx = re.compile('([&#])')
    text = rx.sub(r'\\\1', text)


RX = re.compile('([&#])')
def d(text):
    text = RX.sub(r'\\\1', text)


def mk_esc(esc_chars):
    return lambda s: ''.join(['\\' + c if c in esc_chars else c for c in s])
esc = mk_esc('&#')
def e(text):
    esc(text)


def f(text):
    text = text.replace('&', '\&').replace('#', '\#')


def g(text):
    replacements = {"&": "\&", "#": "\#"}
    text = "".join([replacements.get(c, c) for c in text])


def h(text):
    text = text.replace('&', r'\&')
    text = text.replace('#', r'\#')


def i(text):
    text = text.replace('&', r'\&').replace('#', r'\#')

Timed like this:

python -mtimeit -s"import time_functions" "time_functions.a('abc&def#ghi')"
python -mtimeit -s"import time_functions" "time_functions.b('abc&def#ghi')"
python -mtimeit -s"import time_functions" "time_functions.c('abc&def#ghi')"
python -mtimeit -s"import time_functions" "time_functions.d('abc&def#ghi')"
python -mtimeit -s"import time_functions" "time_functions.e('abc&def#ghi')"
python -mtimeit -s"import time_functions" "time_functions.f('abc&def#ghi')"
python -mtimeit -s"import time_functions" "time_functions.g('abc&def#ghi')"
python -mtimeit -s"import time_functions" "time_functions.h('abc&def#ghi')"
python -mtimeit -s"import time_functions" "time_functions.i('abc&def#ghi')"

Replacing 17 characters

Here's similar code to do the same but with more characters to escape (\`*_{}>#+-.!$):

def a(text):
    chars = "\\`*_{}[]()>#+-.!$"
    for c in chars:
        text = text.replace(c, "\\" + c)


def b(text):
    for ch in ['\\','`','*','_','{','}','[',']','(',')','>','#','+','-','.','!','$','\'']:
        if ch in text:
            text = text.replace(ch,"\\"+ch)


import re
def c(text):
    rx = re.compile('([&#])')
    text = rx.sub(r'\\\1', text)


RX = re.compile('([\\`*_{}[]()>#+-.!$])')
def d(text):
    text = RX.sub(r'\\\1', text)


def mk_esc(esc_chars):
    return lambda s: ''.join(['\\' + c if c in esc_chars else c for c in s])
esc = mk_esc('\\`*_{}[]()>#+-.!$')
def e(text):
    esc(text)


def f(text):
    text = text.replace('\\', '\\\\').replace('`', '\`').replace('*', '\*').replace('_', '\_').replace('{', '\{').replace('}', '\}').replace('[', '\[').replace(']', '\]').replace('(', '\(').replace(')', '\)').replace('>', '\>').replace('#', '\#').replace('+', '\+').replace('-', '\-').replace('.', '\.').replace('!', '\!').replace('$', '\$')


def g(text):
    replacements = {
        "\\": "\\\\",
        "`": "\`",
        "*": "\*",
        "_": "\_",
        "{": "\{",
        "}": "\}",
        "[": "\[",
        "]": "\]",
        "(": "\(",
        ")": "\)",
        ">": "\>",
        "#": "\#",
        "+": "\+",
        "-": "\-",
        ".": "\.",
        "!": "\!",
        "$": "\$",
    }
    text = "".join([replacements.get(c, c) for c in text])


def h(text):
    text = text.replace('\\', r'\\')
    text = text.replace('`', r'\`')
    text = text.replace('*', r'\*')
    text = text.replace('_', r'\_')
    text = text.replace('{', r'\{')
    text = text.replace('}', r'\}')
    text = text.replace('[', r'\[')
    text = text.replace(']', r'\]')
    text = text.replace('(', r'\(')
    text = text.replace(')', r'\)')
    text = text.replace('>', r'\>')
    text = text.replace('#', r'\#')
    text = text.replace('+', r'\+')
    text = text.replace('-', r'\-')
    text = text.replace('.', r'\.')
    text = text.replace('!', r'\!')
    text = text.replace('$', r'\$')


def i(text):
    text = text.replace('\\', r'\\').replace('`', r'\`').replace('*', r'\*').replace('_', r'\_').replace('{', r'\{').replace('}', r'\}').replace('[', r'\[').replace(']', r'\]').replace('(', r'\(').replace(')', r'\)').replace('>', r'\>').replace('#', r'\#').replace('+', r'\+').replace('-', r'\-').replace('.', r'\.').replace('!', r'\!').replace('$', r'\$')

Here's the results for the same input string abc&def#ghi:

  • a) 100000 loops, best of 3: 6.72 μs per loop
  • b) 100000 loops, best of 3: 2.64 μs per loop
  • c) 100000 loops, best of 3: 11.9 μs per loop
  • d) 100000 loops, best of 3: 4.92 μs per loop
  • e) 100000 loops, best of 3: 2.96 μs per loop
  • f) 100000 loops, best of 3: 4.29 μs per loop
  • g) 100000 loops, best of 3: 4.68 μs per loop
  • h) 100000 loops, best of 3: 4.73 μs per loop
  • i) 100000 loops, best of 3: 4.24 μs per loop

And with a longer input string (## *Something* and [another] thing in a longer sentence with {more} things to replace$):

  • a) 100000 loops, best of 3: 7.59 μs per loop
  • b) 100000 loops, best of 3: 6.54 μs per loop
  • c) 100000 loops, best of 3: 16.9 μs per loop
  • d) 100000 loops, best of 3: 7.29 μs per loop
  • e) 100000 loops, best of 3: 12.2 μs per loop
  • f) 100000 loops, best of 3: 5.38 μs per loop
  • g) 10000 loops, best of 3: 21.7 μs per loop
  • h) 100000 loops, best of 3: 5.7 μs per loop
  • i) 100000 loops, best of 3: 5.13 μs per loop

Adding a couple of variants:

def ab(text):
    for ch in ['\\','`','*','_','{','}','[',']','(',')','>','#','+','-','.','!','$','\'']:
        text = text.replace(ch,"\\"+ch)


def ba(text):
    chars = "\\`*_{}[]()>#+-.!$"
    for c in chars:
        if c in text:
            text = text.replace(c, "\\" + c)

With the shorter input:

  • ab) 100000 loops, best of 3: 7.05 μs per loop
  • ba) 100000 loops, best of 3: 2.4 μs per loop

With the longer input:

  • ab) 100000 loops, best of 3: 7.71 μs per loop
  • ba) 100000 loops, best of 3: 6.08 μs per loop

So I'm going to use ba for readability and speed.

Addendum

Prompted by haccks in the comments, one difference between ab and ba is the if c in text: check. Let's test them against two more variants:

def ab_with_check(text):
    for ch in ['\\','`','*','_','{','}','[',']','(',')','>','#','+','-','.','!','$','\'']:
        if ch in text:
            text = text.replace(ch,"\\"+ch)

def ba_without_check(text):
    chars = "\\`*_{}[]()>#+-.!$"
    for c in chars:
        text = text.replace(c, "\\" + c)

Times in μs per loop on Python 2.7.14 and 3.6.3, and on a different machine from the earlier set, so cannot be compared directly.

╭────────────╥──────┬───────────────┬──────┬──────────────────╮
│ Py, input  ║  ab  │ ab_with_check │  ba  │ ba_without_check │
╞════════════╬══════╪═══════════════╪══════╪══════════════════╡
│ Py2, short ║ 8.81 │    4.22       │ 3.45 │    8.01          │
│ Py3, short ║ 5.54 │    1.34       │ 1.46 │    5.34          │
├────────────╫──────┼───────────────┼──────┼──────────────────┤
│ Py2, long  ║ 9.3  │    7.15       │ 6.85 │    8.55          │
│ Py3, long  ║ 7.43 │    4.38       │ 4.41 │    7.02          │
└────────────╨──────┴───────────────┴──────┴──────────────────┘

We can conclude that:

  • Those with the check are up to 4x faster than those without the check

  • ab_with_check is slightly in the lead on Python 3, but ba (with check) has a greater lead on Python 2

  • However, the biggest lesson here is Python 3 is up to 3x faster than Python 2! There's not a huge difference between the slowest on Python 3 and fastest on Python 2!

How do you replace multiple characters in a column in Python?

Pandas replace multiple values in column replace. By using DataFrame. replace() method we will replace multiple values with multiple new strings or text for an individual DataFrame column. This method searches the entire Pandas DataFrame and replaces every specified value.

How do I replace multiple string values in Python?

subn() to replace multiple substrings in a string. sub() - It replaces the contents of a string based on patterns. It takes a pattern or a string as the first argument. The second argument is the lambda function which extracts the matched sub-string then returns the value associated with it from the dictionary.

How do you do multiple replaces in Python?

Method 3: Replace multiple characters using re. subn() is similar to sub() in all ways, except in its way of providing output. It returns a tuple with a count of the total of replacement and the new string rather than just the string.

How do you replace all occurrences of a string in Python?

Python offers easy and simple functions for string handling. The easiest way to replace all occurrences of a given substring in a string is to use the replace() function.