Me and my friend are doing some school work with programming in Python 3.1 and are VERY stuck. We're programming a binary tree and it's working fine except when we want to print all the nodes in inorder in a way that would create a sentence (all the words in inorder just after one another in a row). We have been looking all over the internet for clues as to how to procede and we've been working with this little thing for like two hours. Any advice/help would be awesome. Show Our program/Binary tree:
We get a sort of print when we run the program which looks like this: "bintree.Treenode object at 0x02774CB0", which is not what we want. We use the tree by running this:
Also, the second last row gives us "None" instead of "True", which is wierd. In addition to taking courses on Python, computer science, data structures, and algorithms, I have joined a few communities offering programming challenges to help me improve my coding skills. I enjoy these programming challenges, and recently finished the 30 Days of Code Challenge at HackerRank using both C# and Python. One of the recent challenges I received was to code the inorder traversal of a binary search tree. The binary search tree was already created and I just needed to print all the nodes in correct order, which means I had to do a proper inorder traversal of the binary search tree and print the key of each node along the way. Create Binary Search Tree in PythonFirst things first, I need a binary search tree in Python. Here is a barebones from collections import deque class Node: def __init__(self, key): self.key = key self.left = None self.right = None def add(node, root): if root is None: raise ValueError('root cannot be None.') nodes_found = deque([root]) while len(nodes_found) > 0: current_node = nodes_found.popleft() if current_node.left is None: current_node.left = node break if current_node.right is None: current_node.right = node break nodes_found.append(current_node.left) nodes_found.append(current_node.right) I can create a balanced, binary search tree using keys 1 - 15 using a simple script in Python. root = Node(8) keys = [4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15] for key in keys: add(Node(key), root) I am essentially doing a level-order traversal (like breadth-first search) that adds these keys in a particular order to create a binary search tree. The order of the keys in the list is important. Inorder Traversal of Binary Search TreeNow that I have a binary search tree in Python, I need to perform an inorder traveral of the nodes to display the keys in their correct order. An inorder traveral will display a node's left sub-tree, then the value of its key, followed by the right sub-tree. An inorder traversal makes the most sense for binary search trees, because this is exactly the way binary search trees are ordered. Here is a def display_nodes(root): if root is None: return if root.left is not None: display_nodes(root.left) print(root.key, end=' ') if root.right is not None: display_nodes(root.right) Here is a Python script that displays the nodes of the binary search tree created above. display_nodes(root) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 ConclusionIn the programming challenge the binary search tree
was already provided, so the code I wrote to create the binary search tree wasn't part of the challenge. I just wrote that really quickly in Python to set up the challenge. The only code I needed to write in Python ( I did it in C# as well ) was the Hope this helps! How do I print BST in ascending order?Given an array that stores a complete Binary Search Tree, write a function that efficiently prints the given array in ascending order. Solution: Inorder traversal of BST prints it in ascending order. The only trick is to modify recursion termination condition in standard Inorder Tree Traversal.
How do you inorder a BST?For Inorder, you traverse from the left subtree to the root then to the right subtree. For Preorder, you traverse from the root to the left subtree then to the right subtree. For Post order, you traverse from the left subtree to the right subtree then to the root.
Can we construct BST from inorder?Yes it is possible to construct a binary search tree from an inorder traversal.
How do I print descending order in BST?To improve upon that, we will simulate the reverse in-order traversal of a binary tree as follows:. Create a dummy node.. Create a variable called 'prev' and make it point to the dummy node.. Perform reverse in-order traversal and at each step. Set prev -> right = curr. Set prev -> left = NULL. Set prev = curr.. |