How to count vowels in a string python

Question

This works for me and also counts the consonants as well (think of it as a bonus) however, if you really don't want the consonant count all you have to do is delete the last for loop and the last variable at the top.

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Recommended: Please try your approach on {IDE} first, before moving on to the solution.
How do you count the vowels in a string?
How do you count the number of vowels and consonants in a string in python?
How do you count the number of vowels and consonants in a string?

Her is the python code:

data = input('Please give me a string: ')
data = data.lower()
vowels = ['a','e','i','o','u']
consonants = ['b','c','d','f','g','h','j','k','l','m','n','p','q','r','s','t','v','w','x','y','z']
vowelCount = 0
consonantCount = 0


for string in data:
    for i in vowels:
        if string == i:
            vowelCount += 1
    for i in consonants:
        if string == i:
            consonantCount += 1

print('Your string contains %s vowels and %s consonants.' %(vowelCount, consonantCount))

This is a Python Program to count the number of vowels in a string.

Problem Description

The program takes a string and counts the number of vowels in a string.

Problem Solution

1. Take a string from the user and store it in a variable.
2. Initialize a count variable to 0.
3. Use a for loop to traverse through the characters in the string.
4. Use an if statement to check if the character is a vowel or not and increment the count variable if it is a vowel.
5. Print the total number of vowels in the string.
6. Exit.

Program/Source Code

Here is source code of the Python Program to remove the nth index character from a non-empty string. The program output is also shown below.

string=raw_input("Enter string:")
vowels=0
for i in string:
      if(i=='a' or i=='e' or i=='i' or i=='o' or i=='u' or i=='A' or i=='E' or i=='I' or i=='O' or i=='U'):
            vowels=vowels+1
print("Number of vowels are:")
print(vowels)

Program Explanation

1. User must enter a string and store it in a variable.
2. The count variable is initialized to zero.
3. The for loop is used to traverse through the characters in the string.
4. An if statement checks if the character is a vowel or not.
5. The count is incremented each time a vowel is encountered.
6. The total count of vowels in the string is printed.

Runtime Test Cases

 
Case 1:
Enter string:Hello world
Number of vowels are:
3
 
Case 2:
Enter string:WELCOME
Number of vowels are:
3

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Given a string, count the number of vowels present in given string using Sets.

Prerequisite: Sets in Python

Examples:

Input : GeeksforGeeks
Output : No. of vowels : 5

Input : Hello World
Output : No. of vowels :  3

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:
1. Create a set of vowels using set() and initialize a count variable to 0.
2. Traverse through the alphabets in the string and check if the letter in the string is present in set vowel.
3. If it is present, the vowel count is incremented.

Below is the implementation of above approach:

def vowel_count(str):

count = 0

vowel = set("aeiouAEIOU")

for alphabet in str:

if alphabet in vowel:

count = count + 1

print("No. of vowels :", count)

str = "GeeksforGeeks"

vowel_count(str)

Output:

No. of vowels : 5

How do you count the vowels in a string?

To count the number of vowels in a given sentence:.

Read a sentence from the user..

Create a variable (count) initialize it with 0;.

Compare each character in the sentence with the characters {'a', 'e', 'i', 'o', 'u' }.

If a match occurs increment the count..

Finally print count..

How do you count the number of vowels and consonants in a string in python?

To count the number of vowels and consonants in a string, we iterate using a for loop through each character of the string and check if it matches a vowel. If yes then, we increment the vowel counter otherwise increment the consonant counter.