The different 3-digit numbers which can be formed by using the digits 0, 2, 5 without repeating any digit in the number are 205, 250, 502 and 520. Therefore, four 3 digit numbers can be formed by using the digits 0, 2, 5. How many 30,to,9⇒10nos8×9=728×8×4=25672+256=328. Was this answer helpful?
How many 3There are 504 different 3-digit numbers which can be formed from numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 if no repetition is allowed.
How many 3For the 3-digit area code, the first digit can be any digit from 2 through 9, and each of the two digits that follow can be any digit from 0 through 9. That's a total of 8 × 10 × 10 = 800 different combinations.
How many combinations are there from 0 to 9?There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
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