Find the least number which when divided by 40 50 and 60 leaves remainder 5 in each case

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Christopher H.

Algebra

7 months, 2 weeks ago



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Find the least number which when divided by 40 50 and 60 leaves remainder 5 in each case

Find the least number which when divided by 40 50 and 60 leaves remainder 5 in each case

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Find the least number which when divided by 30, 36, 56, &63 leaves 8 as remainder in each case

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Video Transcript

in this question find the least number. Yeah least number. When we divided 30 56, 36 and 63 it leaves remainder. It leaves a remainder that is eight. So first of all we find out the L. C. M. Of 30 56 36 63. So 30 the factor of 30 is two times five times three 56. So this is two times two times two times seven 36. So you will get two times three times three times three. Now there is a 63 there is the last number, so three times three times seven. So the L. C. M. Of Elsie um of 30 56 36 and 63. So this is two times two times two times three times three times three times five times seven. So when you multiply this you will get 7560. So this is the number. When you divide these all these all By 7560. Then it leaves the remainder that is eight. So it leaves the remainder that is it. So this is 7568. So so the required answer is 7568. This is the least number. When you divide, When you divide all these phone number it leaves the remainder eight. So 7568 is the final answer

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Find the least number which when divided by 40 50 and 60 leaves remainder 5 in each case

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Video Transcript

Find the greatest number of 4 of 4 digits, which is exactly divisible by 4048 and 60 point well. The first thing we need to do is find the least common multiple for each 1 of these, and to do that, let's break them down into their prime numbers. I will say: 40 is 4 times, 104 is 2 times. 210 is 2 times. 548 point went to say it's 6 times 8. That will be 2 times 32 times 4 and 2 times. 2.60 is 6 times. 10 there'll be 2 times 3 and 2 times 5. So i want to say: 40 is 2 times 2 times 2 times 548 is going to be 2. I got that 2 times 3. Well, i don't have any 3 written, so i'm going to put it over here to the side and then i have 2. So we'll put it underneath this 22 underneath this 22. I need to put out to the side because i don't have any more 2 and then 60 is going to be 2. So i won put that here. 3 put that under the 32 under the 2 and 5 under the 5, so oh least, common multiple, i'm simply gonna multiply the numbers in each column, 22253 and 2. So we multiply those together. So that's gone, be 6 times. 5 is 30612240 point well. 240. Is not a 4 digit number, so i need to see how much can i i need to make this a 4 digit number. Anything i multiplied by 240 is going to be divisible by 4048 and 60 point. So if i multiply this by 10, i get 2400 point. Well, that's not going to be the largest. I can multiply this by what i can multiply that by 3. If i multiply that by 3, then we're going to have 007200 point well, can i give anything bigger? So what if i take 240 and multiply it by 40 point? Well, that would be 06. There'S 9600 point: i let's see, i think we might can get by 41 point. Let'S try it. Let'S track 4340 times 41 point there'll be 240, it's gonna be 016 and 9048 and 9 point there. You go so when i take my least common multiple and keep multiplying it till i get the biggest 4 digit number. We ended up, multiplying it. Byty 1 point.

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  • Video Transcript
  • RD Sharma Solutions Class 6 Mathematics Solutions for Playing with numbers Exercise 2.10 in Chapter 2 - Playing with numbers
  • Which is the least number which when divided by 40 50 and 60 leaves the remainder 5 in each case?
  • What is the smallest number which is completely divisible by 40 50 and 60?
  • What is the smallest number which when divided by 25 40 and 60 leaves remainder 7 in each case?
  • Which is the smallest number that is exactly divisible by 24 45 and 60?

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  • Playing with numbers Exercise 2.1
  • Playing with numbers Exercise 2.8
  • Playing with numbers Exercise 2.2
  • Playing with numbers Exercise 2.3
  • Playing with numbers Exercise 2.4
  • Playing with numbers Exercise 2.5
  • Playing with numbers Exercise 2.6
  • Playing with numbers Exercise 2.7
  • Playing with numbers Exercise 2.9
  • Playing with numbers Exercise 2.10
  • Playing with numbers Exercise 2.11
  • Knowing your numbers
  • Playing with numbers
  • Whole Numbers
  • Operations on whole numbers
  • Negative number and integers
  • Fractions
  • Decimals
  • Introduction to Algebra
  • Ratio, Proportion and Unitary Method
  • Basic Geometrical Concepts
  • Angles
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  • Pair of Lines and Transversal
  • Understanding Three Dimensional Shapes
  • Symmetry
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  • Data Handling – II
  • Data Handling Bar Graphs

RD Sharma Solutions Class 6 Mathematics Solutions for Playing with numbers Exercise 2.10 in Chapter 2 - Playing with numbers

Question 1 Playing with numbers Exercise 2.10

What is the smallest number which when divided by 24, 36 and 54 gives a remainder of 5 each time?

Answer:

Prime factorization of

24 = 2 × 2 × 2 × 3

36 = 2 × 2 × 3 × 3

54 = 2 × 3 × 3 × 3

So the required LCM = 2 × 2 × 2 × 3 × 3 × 3 = 216

The smallest number which is exactly divisible by 24, 36 and 54 is 216

In order to get remainder as 5

Required smallest number = 216 + 5 = 221

Therefore, the smallest number which when divided by 24, 26 and 54 gives a remainder of 5 each time is 221.

Video transcript

"Welcome to lido homework. My name is leonie Rolla and in today's Q&A video. We are going to solve a word problem. So let us repeat the question together. What is the smallest number which when divided by 24 36 and 54 gives a remainder of 5 each time. So as you can see that in the question, we are supposed to find s smallest number and that smallest number should be common right foot. Before 36 and 54 in what way says in such a way that whenever we divide that number by 24 we divide that number by 36 and we divide that number by 50 for we should get a remainder of 5 each time. So let us think about it, right? How can we do this? So before I start finding that number for who's the remainder after dividing by 24 36 54 we get the remainder as 5 let us And a number that is divisible by 24 by 36 by 54 right? In fact, let us find the least common number that is or least common multiple of 24 36 and 54. So right now what I'm going to do is I'm going to find the LCM of 24 36 and 54. Let us see how we can do that. So 24 the prime factorization of 24 is as follows 212 size twenty four to six Squeals to these ice 6 similarly for 36 it is going to be to 80s is thirty six to nine size 1833 size 9 similarly for 54 2 to the 4 to 7 of 14 three nines ice 27 3 3 0 is 9 therefore 24 can be written as 2 into 2 into 2 into 3. Similarly 36 can be written as 2 into 2 2 into 3 into 3 and few to 4 can be written as 2 into 3 into 3 into 3, right? Let us first find what are the comments here? So we have two two two common and we have three three three common and it has we have three and three common in the second number and the first and second number. We have two common. Therefore. The LCM e is 2/3 This to this tree and the leftovers in the first case that is two in the second case the third case that is three, right? So let us try to multiply this and see how much we will get to these I-66 to size 12 12 into 3 is 36 their son into here, right? So till here it is 36 and 2 into 3 is 6 now, let us see how we can find the value of 36 into 6. So 6 is 6 3 9 6 3 is 18 216 there for two and six is the least common multiple for 24 36 and 54. But the question is not asking us to find the least common multiple. In fact, the question is asking us to find the smallest number the least number which when divided by 24 36 and 54 which will give me five. Now if I divide 2 and 6 by 24 I'm going to get the remainder is 0 similarly if I divide 2 and 6 by 36 I'm going to get the remainder is 0 and also if I divide 216 by 51, I'm going to get the remainder as 0 right. So now what am I supposed to do so that I'll get the remainder as five. My load sticks tells me that I just need to add 5 to 216 which will give me 2 to 1 therefore if I divide 2 to 1 by 24, I'll get the remainder as five. Strangest chicken legs two to one. Let us try to divide it by 24 so we can know that 24 how many times will give me 2 to 1 any idea there is none, right? So let us find just next to that let us find the multiple of 20 for this next 2 to 21 and it will give me it might be to the 6 from here. Also. I can find it very easily to the for photos of eight a tree size 24. They did you guess so if I divide. Let's say Let's Take by 9:00. Okay, 9:00 for size 36 399 to jst in 216 Creek. So if I multiply 24 into 9, I will get it as 216 and I'm getting the remainder is 5 isn't it similarly when I divide 2 to 1 by 36 and when I divide 54 by 3054 221 by 54R still get the remainder is 5 and that is what the question is asking us. Hence now. Now we can conclude that. Hence. 221 is the required smallest number, right? It is the required smallest number. That's it. So what is the Mercury since this is a word problem. You have to give the answer in terms of statements as well. Okay you to give the answer in terms of statement only. Okay guys, that's it for today's Q&A video. If there is any doubt, please do comment below and if you liked the video and for such upcoming videos to subscribe to Lido "

Was This helpful?

Which is the least number which when divided by 40 50 and 60 leaves the remainder 5 in each case?

Hence, 605 is the least number which when divided by 40, 50 and 60 leaves remainder 5 in each case.

What is the smallest number which is completely divisible by 40 50 and 60?

LCM of 40, 50 and 60 is 600. The smallest number among all common multiples of 40, 50, and 60 is the LCM of 40, 50, and 60. (40, 80, 120, 160, 200…), (50, 100, 150, 200, 250…), and (60, 120, 180, 240, 300…), respectively, are the first few multiples of 40, 50, and 60.

What is the smallest number which when divided by 25 40 and 60 leaves remainder 7 in each case?

Therefore the least number which when divided by 25 , 40 and 60 leaves remainder 7 in each case is 607 .

Which is the smallest number that is exactly divisible by 24 45 and 60?

Hence, the answer is 3600. Was this answer helpful?

What is the smallest number which when divided by 30 45 and 60 leaves remainder 5 in each case?

So the answer is 187.

When divided by 25 40 and 60 leaves 9 as the remainder in each case?

Hence, 609 is the least number which when divided by 25, 40 and 60 leaves 9 as remainder in each case.

What is the smallest number which when divided by 25 40 and 60 leaves remainder 7 in each case?

Hence, the smallest number which when divided by 25, 40 and 60 leaves remainder 7 in each case is 607.

What is the smallest number which when divided by 20 25 35 and 40 leaves?

The smallest number which when divided by 20,25,35 and 40 leaves a remainder of 14,19,29 and 34 respectively, is 1394 .