A single line contains integers separated by space in javascript

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How do I take the input of a line of integers separated by a space in Java?
How do you take space separated integer inputs?
How do I take the input of a line of integers separated by a space in Python?
How do you take space separated input in for loop in Python?

I have easy question, but can't find the solution. Need to print all numbers from 1 to N (10) but not in a row. The output needs to bee in single line separated by spaces - 1 2 3 4 5...

let n = 10;
for (let i = 1; i <= n; i++) {
    console.log(i);
}

Can I do it without using array?

asked Dec 10, 2018 at 20:42

Николай МатевНиколай Матев

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1

Concatenate with a string in the loop instead, then console.log that string:

let n = 10;
let str = '';
for (let i = 1; i <= n; i++) {
  str += i + ' ';
}
console.log(str.trim());

answered Dec 10, 2018 at 20:43

1

A different approach could be to create an array using fill and map to create an array, then join the values to create the string.

let n = 10
let r = new Array(n).fill(null).map((val, idx) => idx + 1).join(' ')

console.log(r)

answered Dec 10, 2018 at 20:53

Get Off My LawnGet Off My Lawn

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1

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There are 2 methods to take input from the user which are separated by space which are as follows:

Using BufferedReader Class and then splitting and parsing each value
Using nextInt( ) method of Scanner class

Let us discuss both the methods one by one in order to get a better understanding by implementing the same clean java programs.

Method 1:

Using BufferedReader Class and then splitting and parsing each value.

Procedure:

Using readline() method of BufferedReader and Scan the whole string.
Split this String for str.split(” “)
Iterate over the above array and parse each integer value using Integer.parseInt( ).

Example

Java

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

class GFG {

public static void main(String[] args)

throws IOException

{

BufferedReader bi = new BufferedReader(

new InputStreamReader(System.in));

int num[] = new int[10];

String[] strNums;

System.out.println("enter string of numbers");

strNums = bi.readLine().split(" ");

for (int i = 0; i < strNums.length; i++) {

num[i] = Integer.parseInt(strNums[i]);

}

System.out.println("printing stored numbers ");

for (int i = 0; i < strNums.length; i++) {

System.out.println(num[i]);

}

Output:

FIG = OUTPUT OF METHOD 1

Method 2: Using nextInt() method of Scanner class.

Procedure:

Using the nextInt() method of Scanner class and scan to scan the input.
Using for loop to store input in an array.
Iterate through the above array and parse each integer using sc.nextInt()

Example

Java

import java.io.IOException;

import java.util.Scanner;

class GFG {

public static void main(String[] args)

throws IOException

{

System.out.println("enter input ");

Scanner sc = new Scanner(System.in);

int[] nums = new int[10];

int i;

for (i = 0; i < nums.length; i++) {

nums[i] = sc.nextInt();

}

System.out.println("printing stored values");

for (i = 0; i < nums.length; i++) {

System.out.println(nums[i] + " ");

}

Output:

FIG = OUTPUT OF METHOD 2

Note: The first method using Bufferedreader class and then splitting and parsing each value is much faster than using nixing() method of Scanner class. It is nearly 2 times faster than the second one. Bel;ow we do provide in order how to calculate the time consume by both methods by using nanotime method

// Initializing variables
long startTime, endTime;

// Start time
startTime = System.nanoTime(); {

// Insert code here
// Method 1 or method 2 code
}

// End time
endTime = System.nanoTime();

How do I take the input of a line of integers separated by a space in Java?

There are 2 methods to take input from the user which are separated by space which are as follows: Using BufferedReader Class and then splitting and parsing each value. Using nextInt( ) method of Scanner class.

How do you take space separated integer inputs?

scanf uses any whitespace as a delimiter, so if you just say scanf("%d", &var) it will skip any whitespace and then read an integer (digits up to the next non-digit) and nothing more. Note that whitespace is any whitespace -- spaces, tabs, newlines, or carriage returns.

How do I take the input of a line of integers separated by a space in Python?

Use an input() function to accept the list elements from a user in the format of a string separated by space. Next, use a split() function to split an input string by space. The split() method splits a string into a list.