Which smallest integer must be subtracted from both the TE ratio 6/7 so that the new ratio is less than 16 21?

  • Test: Unitary Method- 2

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Related Find the smallest positive integer which must be subtracted from both the terms of ratio 6 : 7. So that the result gives a ratio, less than 16 : 21a)2b)4c)3d)5e)None of theseCorrect answer is option 'C'. Can you explain this answer?

Let the whole number is X.

Now, according to question,

(6 -X) /(7 -X) < 16/21.

21 *(6 -X) < 16 *(7 -X)

126 - 21X < 112 - 16X

126 - 112 < - 16X + 21X

14 < 5X

5X  > 14

X > 2.8

So, Least such whol number would be 3.

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My answer is coming 2.8 .It's close to 3

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Question Description
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Which smallest integer must be subtracted from both the TE ratio 6/7 so that the new ratio is less than 16 21?

Let the whole number is X.Now, according to question,(6 -X) /(7 -X) < 16/21.21 *(6 -X) < 16 *(7 -X)126 - 21X < 112 - 16X126 - 112 < - 16X + 21X14 < 5X5X > 14X > 2.8So, Least such whol number would be 3.

  • Aptitude
  • Ratio and Proportions


A) 5

B) 4

C) 3

D) 2

Correct Answer:

C) 3

Description for Correct answer:
\( \Large \frac{6 - x}{7 - x} < \frac{16}{21} \)

126 - 21x < 112 - 16x

126 - 112 < 21x - 16x

14 < 5x

\( \Large \frac{14}{5} < x \)

2.8 < x

x = 3 (From option)

Part of solved Ratio and Proportions questions and answers : >> Aptitude >> Ratio and Proportions

Which smallest integer must be subtracted from both the TE ratio 6/7 so that the new ratio is less than 16 21?

Answer : The smallest positive integer is 3.

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What is the smallest number which when subtracted?

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