What number should be added to 2x³ 3x² X so that the resulting polynomial is divided by x 2 leaves a remainder 3?

(i) let us assume ‘p’ be subtracted from 2 x^{2}-5 x

So, dividing 2 x^{2}-5 x by 2x + 1.

\begin{array}{c} 2 x+1) 2 x^{2}-5 x-p(x-3 \\ 2 x^{2}+x \\ \frac{-}{-6 x-p} \\ -6 x-3 \\ \frac{+}{-p+3} \end{array}

Hence, remainder is 3 – p

From the question, it is given that, the remainder is 2.

3 – p = 2

p = 3 – 2

p = 1

Therefore, 1 is to be subtracted.

(ii) let us assume ‘p’ be subtracted from 2 x^{3}-7 x^{2}+2 x,

So, dividing it by 2x – 3,

\begin{array}{c} 2 x-3) 2 x^{3}-7 x^{2}+2 x+p\left(x^{2}-2 x-2\right. \\ 2 x^{3}-3 x^{2} \\ \frac{-1}{-4 x^{2}+2 x} \\ -4 x^{2}+6 x \\ +\frac{-}{-4 x+p} \\ -4 x+6 \\ \frac{+}{2-6} \end{array}

Hence, remainder is p – 6

From the question it is given that, remainder is - 2.

P – 6 = - 2

P = -2 + 6

P = 4

Therefore, 4 is to be added.

Sum

What number should be added to 3x3 – 5x2 + 6x so that when resulting polynomial is divided by x – 3, the remainder is 8? 

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Solution

Let the numbw-er k be added and resulting polnomic be f(x). 

So, f(x) =`3x^3+5x^2+6x+k`  

it is given that when f(x)is dividing by (x-3), the remainder is 8. 

∴ f(3)=8 

`3(3)^3-5(3)^2+6(3)+k=8` 

`81-45+18+k=8` 

`54+k=8`

`k=-46` 

Thus, the required number is  -46. 

Concept: Remainder Theorem

  Is there an error in this question or solution?

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Chapter 8: Remainder and Factor Theorems - Exercise 8 (A) [Page 109]

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Chapter 8 Remainder and Factor Theorems
Exercise 8 (A) | Q 13 | Page 109

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Sum

What number must be added to 2x3 – 7x2 + 2x so that the resulting polynomial leaves the remainder – 2 when divided by 2x – 3?

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Solution

Let a be added to 2x3 – 7x2 + 2x dividing it by 2x – 3, then

`2x - 3")"overline(2x^3 - 7x^2 + 2x + a)"(x^2 - 2x - 2`
             2x3 – 3x2 
             –    +                          
                   –4x2 + 2x
                   –4x2 + 6x
                   +      –                  
                           –4x + a
                           –4x + 6
                           +    –             
                              a – 6           
But remainder is –2, then
a – 6 = –2
⇒ a = –2 + 6
⇒ a = 4
Hence 4 is to be added.

Concept: Remainder Theorem

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Chapter 6: Factorization - Exercise 6.1

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Chapter 6 Factorization
Exercise 6.1 | Q 7.2

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Which number should be added ...

Updated On: 27-06-2022

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What number should be added to 2x³ 3x² X so that the resulting polynomial is divided by x 2 leaves a remainder 3?

Text Solution

Answer : `f(x)=x^2-5x+6`

Answer

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What number should be added to 2x³ 3x² X so that when the resulting polynomial is divided by x 2 The remainder is 3?

Answer: 7 must be added.

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Answer. Hence, 4x-2 is added to the given polynomial p(x) to leave the remainder=(-2).

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Expert-verified answer -6 must be added to the polynomial so that the resulting polynomial is exactly divisible by .

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So, The no. is 7.