Chương trình C# để tính tổng của tất cả các số chia hết cho 3 trong phạm vi đã cho Show Mã số 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
tĩnh void Chính(chuỗi[] args) { int sum = 0; Bảng điều khiển. Viết("Số 1. "); int num1 = Chuyển đổi.ToInt32(Bảng điều khiển. Dòng đọc()); Bảng điều khiển. Viết("Số 2. "); int num2 = Chuyển đổi.ToInt32(Bảng điều khiển. Dòng đọc()); cho(int i=num1;i<=num2;i++) { nếu(i%3==0) { tổng += i; } } Bảng điều khiển. WriteLine("Tổng các số " +sum); Bảng điều khiển. ReadKey(); }
đầu ra  Bạn có thể tìm thêm các ví dụ tương tự về lập trình cho ngôn ngữ lập trình này trên trang web Như thế nàyThích Đang tải. Cho ba số A, B, M sao cho A < B, nhiệm vụ là tìm tổng các số chia hết cho M trong khoảng [A, B] ví dụ.
Khuyến khích. Vui lòng thử cách tiếp cận của bạn trên {IDE} trước, trước khi chuyển sang giải pháp Cách tiếp cận ngây thơ. Kiểm tra xem mỗi số trong dãy [A, B] có chia hết cho M hay không. Và cuối cùng, cộng tất cả các số chia hết cho M Dưới đây là việc thực hiện các phương pháp trên. C++
M, 2M, 3M, ...0 M, 2M, 3M, ...1
M, 2M, 3M, ...2
M, 2M, 3M, ...4 M, 2M, 3M, ...5_______0_______4 M, 2M, 3M, ...7 M, 2M, 3M, ...4 M, 2M, 3M, ...9 M, 2M, 3M, ...4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.1 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.7
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.9 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M1 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M3 N = B / M - (A - 1)/ M4 M, 2M, 3M, ...4 N = B / M - (A - 1)/ M6
N = B / M - (A - 1)/ M7_______20_______8 N = B / M - (A - 1)/ M7_______29_______0 N = B / M - (A - 1)/ M7_______29_______2 sum = N * ( (first term + last term) / 2)3 sum = N * ( (first term + last term) / 2)4_______29_______5
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)7 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)9 420 421
422 M, 2M, 3M, ...4 424 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 427 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 429 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 // C++ program to find the sum of numbers2
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____687_______4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____687_______6
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)9 // C++ program to find the sum of numbers9421 Java
M, 2M, 3M, ...2
M, 2M, 3M, ...4 M, 2M, 3M, ...5_______0_______4 M, 2M, 3M, ...7 M, 2M, 3M, ...4 M, 2M, 3M, ...9 M, 2M, 3M, ...4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.1 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 using4using5using6
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.9 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M1 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M3 N = B / M - (A - 1)/ M4 M, 2M, 3M, ...4 N = B / M - (A - 1)/ M6
N = B / M - (A - 1)/ M7_______20_______8 N = B / M - (A - 1)/ M7_______29_______0 N = B / M - (A - 1)/ M7_______29_______2 M, 2M, 3M, ...14 using5M, 2M, 3M, ...16 sum = N * ( (first term + last term) / 2)4_______29_______5
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)7 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)9 420 421
422 M, 2M, 3M, ...28 #include <bits/stdc++.h>0 M, 2M, 3M, ...30 M, 2M, 3M, ...31 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 427 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 429 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 M, 2M, 3M, ...39 M, 2M, 3M, ...40 M, 2M, 3M, ...41 M, 2M, 3M, ...42 M, 2M, 3M, ...43 M, 2M, 3M, ...44 using6
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____687_______4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...50_______0_______51 M, 2M, 3M, ...52 421 421
M, 2M, 3M, ...55 Python3M, 2M, 3M, ...56 M, 2M, 3M, ...57
M, 2M, 3M, ...58 M, 2M, 3M, ...57 M, 2M, 3M, ...60 M, 2M, 3M, ...61
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...63 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...65 M, 2M, 3M, ...66 using5
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...69 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...71 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M3 M, 2M, 3M, ...74_______0_______75 M, 2M, 3M, ...76 M, 2M, 3M, ...77 M, 2M, 3M, ...78 M, 2M, 3M, ...79_______0_______80
N = B / M - (A - 1)/ M7_______0_______82 N = B / M - (A - 1)/ M7_______0_______84 N = B / M - (A - 1)/ M7_______29_______2 M, 2M, 3M, ...87_______0_______88 M, 2M, 3M, ...89 M, 2M, 3M, ...66 M, 2M, 3M, ...66 using5M, 2M, 3M, ...80 sum = N * ( (first term + last term) / 2)4_______0_______65 M, 2M, 3M, ...78 M, 2M, 3M, ...66 M, 2M, 3M, ...74
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.00 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)9 M, 2M, 3M, ...65
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.04 sum = N * ( (first term + last term) / 2)2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.06 M, 2M, 3M, ...66 M, 2M, 3M, ...66 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.09 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.10 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.13 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.15 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.17 M, 2M, 3M, ...66 M, 2M, 3M, ...40 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.21 M, 2M, 3M, ...66 M, 2M, 3M, ...42 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...89 M, 2M, 3M, ...66 M, 2M, 3M, ...44
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.29 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.31 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.32 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.34 C#K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.35
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.38
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.41 M, 2M, 3M, ...2
M, 2M, 3M, ...4 M, 2M, 3M, ...5_______0_______4 M, 2M, 3M, ...7 M, 2M, 3M, ...4 M, 2M, 3M, ...9 M, 2M, 3M, ...4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.1 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.7 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.41 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.9 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M1 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M3 N = B / M - (A - 1)/ M4 M, 2M, 3M, ...4 N = B / M - (A - 1)/ M6 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.41 N = B / M - (A - 1)/ M7_______20_______8 N = B / M - (A - 1)/ M7_______29_______0 N = B / M - (A - 1)/ M7_______29_______2 sum = N * ( (first term + last term) / 2)3 sum = N * ( (first term + last term) / 2)4_______29_______5 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.41 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)7 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)9 420 421 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.41 422 M, 2M, 3M, ...28 #include <bits/stdc++.h>0 M, 2M, 3M, ...30 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.91 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 427 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 429 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 // C++ program to find the sum of numbers2K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.41 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____687_______4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M04 M, 2M, 3M, ...51 M, 2M, 3M, ...52 421 421
N = B / M - (A - 1)/ M10 JavascriptN = B / M - (A - 1)/ M11
N = B / M - (A - 1)/ M12
M, 2M, 3M, ...2
N = B / M - (A - 1)/ M16 N = B / M - (A - 1)/ M17 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M23 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.7
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.9 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M1 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M3 N = B / M - (A - 1)/ M4 N = B / M - (A - 1)/ M23 N = B / M - (A - 1)/ M6 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M7_______20_______8 N = B / M - (A - 1)/ M7_______29_______0 N = B / M - (A - 1)/ M7_______29_______2 sum = N * ( (first term + last term) / 2)3 sum = N * ( (first term + last term) / 2)4_______29_______5
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)7 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)9 420 421
422
427 429 N = B / M - (A - 1)/ M23 // C++ program to find the sum of numbers2
N = B / M - (A - 1)/ M56
N = B / M - (A - 1)/ M57
N = B / M - (A - 1)/ M58 đầu ra. 42
Thời gian phức tạp. O(B-A) Phương pháp tiếp cận hiệu quả. Ý tưởng là sử dụng khái niệm Cấp số cộng và chia hết.
M, 2M, 3M, ...
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.
N = B / M - (A - 1)/ M
sum = N * ( (first term + last term) / 2) Dưới đây là việc thực hiện các phương pháp trên. C++
M, 2M, 3M, ...0 M, 2M, 3M, ...1
N = B / M - (A - 1)/ M65 N = B / M - (A - 1)/ M66 N = B / M - (A - 1)/ M67 M, 2M, 3M, ...4 N = B / M - (A - 1)/ M69_______0_______4 N = B / M - (A - 1)/ M71_______0_______4 N = B / M - (A - 1)/ M73 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M76 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M78 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 N = B / M - (A - 1)/ M81
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M83 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M85 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 N = B / M - (A - 1)/ M88 N = B / M - (A - 1)/ M7_______29_______9 N = B / M - (A - 1)/ M91 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M93
N = B / M - (A - 1)/ M7_______20_______95 N = B / M - (A - 1)/ M7_______20_______97 N = B / M - (A - 1)/ M7_______20_______99 N = B / M - (A - 1)/ M7_______29_______9 sum = N * ( (first term + last term) / 2)02 421
sum = N * ( (first term + last term) / 2)04 sum = N * ( (first term + last term) / 2)05 N = B / M - (A - 1)/ M67 M, 2M, 3M, ...4 sum = N * ( (first term + last term) / 2)08 M, 2M, 3M, ...4 N = B / M - (A - 1)/ M71_______0_______4 N = B / M - (A - 1)/ M73 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M76 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M78 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 sum = N * ( (first term + last term) / 2)20
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M83 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M85 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 N = B / M - (A - 1)/ M88 N = B / M - (A - 1)/ M7_______29_______9 N = B / M - (A - 1)/ M91 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M93
N = B / M - (A - 1)/ M7_______20_______95 N = B / M - (A - 1)/ M7_______20_______97 N = B / M - (A - 1)/ M7_______20_______99 N = B / M - (A - 1)/ M7_______29_______9 sum = N * ( (first term + last term) / 2)41 421
M, 2M, 3M, ...2
M, 2M, 3M, ...4 M, 2M, 3M, ...5_______0_______4 M, 2M, 3M, ...7 M, 2M, 3M, ...4 M, 2M, 3M, ...9 M, 2M, 3M, ...4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.1 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.7 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 sum = N * ( (first term + last term) / 2)61 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 sum = N * ( (first term + last term) / 2)64
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)66 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)68 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 sum = N * ( (first term + last term) / 2)71 N = B / M - (A - 1)/ M7_______29_______73
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 sum = N * ( (first term + last term) / 2)76 N = B / M - (A - 1)/ M7_______29_______78
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)80 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 sum = N * ( (first term + last term) / 2)83
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)85 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)9 sum = N * ( (first term + last term) / 2)88 421
422 M, 2M, 3M, ...4 424 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)95 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 429 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 // C++ program to find the sum of numbers2
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____687_______4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 4204
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)9 // C++ program to find the sum of numbers9421 Java
N = B / M - (A - 1)/ M65 N = B / M - (A - 1)/ M66 N = B / M - (A - 1)/ M67
M, 2M, 3M, ...4 N = B / M - (A - 1)/ M69_______0_______4 N = B / M - (A - 1)/ M71 M, 2M, 3M, ...4 N = B / M - (A - 1)/ M73 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M76 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M78 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 N = B / M - (A - 1)/ M81
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M83 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M85 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 4239 using5M, 2M, 3M, ...16 N = B / M - (A - 1)/ M7_______29_______9 N = B / M - (A - 1)/ M91 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M93
N = B / M - (A - 1)/ M7_______20_______95 N = B / M - (A - 1)/ M7_______20_______97 N = B / M - (A - 1)/ M7_______20_______99 N = B / M - (A - 1)/ M7_______29_______9 sum = N * ( (first term + last term) / 2)02 421
sum = N * ( (first term + last term) / 2)04 sum = N * ( (first term + last term) / 2)05 N = B / M - (A - 1)/ M67
M, 2M, 3M, ...4 sum = N * ( (first term + last term) / 2)08_______0_______4 N = B / M - (A - 1)/ M71 M, 2M, 3M, ...4 N = B / M - (A - 1)/ M73 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M76 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M78 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 sum = N * ( (first term + last term) / 2)20
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M83 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M85 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 4239 using5M, 2M, 3M, ...16 N = B / M - (A - 1)/ M7_______29_______9 N = B / M - (A - 1)/ M91 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M93
N = B / M - (A - 1)/ M7_______20_______95 N = B / M - (A - 1)/ M7_______20_______97 N = B / M - (A - 1)/ M7_______20_______99 N = B / M - (A - 1)/ M7_______29_______9 sum = N * ( (first term + last term) / 2)41 421
M, 2M, 3M, ...2
M, 2M, 3M, ...4 M, 2M, 3M, ...5_______0_______4 M, 2M, 3M, ...7 M, 2M, 3M, ...4 M, 2M, 3M, ...9 M, 2M, 3M, ...4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.1 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 sum = N * ( (first term + last term) / 2)61 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 sum = N * ( (first term + last term) / 2)64
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)66 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)68 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 sum = N * ( (first term + last term) / 2)71 N = B / M - (A - 1)/ M7_______29_______73
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 sum = N * ( (first term + last term) / 2)76 N = B / M - (A - 1)/ M7_______29_______78
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)80 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 // C++ program to find the sum of numbers45M, 2M, 3M, ...79 // C++ program to find the sum of numbers47
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)85 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)9 // C++ program to find the sum of numbers53// C++ program to find the sum of numbers54using6421
422 M, 2M, 3M, ...28 #include <bits/stdc++.h>0 M, 2M, 3M, ...30 M, 2M, 3M, ...31 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.2 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)95 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 429 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...4 M, 2M, 3M, ...39 M, 2M, 3M, ...40 M, 2M, 3M, ...41 M, 2M, 3M, ...42 M, 2M, 3M, ...43 M, 2M, 3M, ...44 using6
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____687_______4 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 // C++ program to find the sum of numbers81
421 421
Python3
M, 2M, 3M, ...57
M, 2M, 3M, ...60 // C++ program to find the sum of numbers92K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____687_______95 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 // C++ program to find the sum of numbers97K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 // C++ program to find the sum of numbers99_______0_______66 // divisible by M in the given range01M, 2M, 3M, ...88 // divisible by M in the given range03
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____688_______05 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____688_______07 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 // divisible by M in the given range10M, 2M, 3M, ...66 M, 2M, 3M, ...66 using5M, 2M, 3M, ...80 N = B / M - (A - 1)/ M7_______29_______9 // divisible by M in the given range01K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M93 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.10 N = B / M - (A - 1)/ M7_______688_______22 N = B / M - (A - 1)/ M7_______688_______24 N = B / M - (A - 1)/ M7_______688_______26 N = B / M - (A - 1)/ M7_______29_______9 // divisible by M in the given range01// divisible by M in the given range30 // C++ program to find the sum of numbers99
M, 2M, 3M, ...60 // divisible by M in the given range36K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____687_______95 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 // C++ program to find the sum of numbers97K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 // C++ program to find the sum of numbers99M, 2M, 3M, ...66 // divisible by M in the given range45M, 2M, 3M, ...78 N = B / M - (A - 1)/ M73 M, 2M, 3M, ...88 // divisible by M in the given range03
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____688_______05 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3____688_______07 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 // divisible by M in the given range10M, 2M, 3M, ...66 M, 2M, 3M, ...66 using5M, 2M, 3M, ...80 N = B / M - (A - 1)/ M7_______29_______9 // divisible by M in the given range01K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 N = B / M - (A - 1)/ M93 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.10 N = B / M - (A - 1)/ M7_______688_______22 N = B / M - (A - 1)/ M7_______688_______24 N = B / M - (A - 1)/ M7_______688_______26 N = B / M - (A - 1)/ M7_______29_______9 // divisible by M in the given range01M, 2M, 3M, ...78 // divisible by M in the given range03// divisible by M in the given range30 // C++ program to find the sum of numbers99
M, 2M, 3M, ...58 M, 2M, 3M, ...57 M, 2M, 3M, ...60 M, 2M, 3M, ...61 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...63 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 M, 2M, 3M, ...65 M, 2M, 3M, ...66 using5K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 // divisible by M in the given range92M, 2M, 3M, ...66 // divisible by M in the given range94K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 // divisible by M in the given range96M, 2M, 3M, ...66 // divisible by M in the given range98
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 #include <bits/stdc++.h>00K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 #include <bits/stdc++.h>02K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 #include <bits/stdc++.h>05N = B / M - (A - 1)/ M7_______688_______92 M, 2M, 3M, ...78 M, 2M, 3M, ...66 M, 2M, 3M, ...89
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)2 #include <bits/stdc++.h>13N = B / M - (A - 1)/ M7_______688_______92____688_______30 M, 2M, 3M, ...66 M, 2M, 3M, ...89
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 #include <bits/stdc++.h>20K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 #include <bits/stdc++.h>22M, 2M, 3M, ...66 #include <bits/stdc++.h>24#include <bits/stdc++.h>25#include <bits/stdc++.h>25 K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.1 // divisible by M in the given range30 #include <bits/stdc++.h>29// divisible by M in the given range30 M, 2M, 3M, ...79 M, 2M, 3M, ...16 #include <bits/stdc++.h>25#include <bits/stdc++.h>25 M, 2M, 3M, ...89
K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 #include <bits/stdc++.h>37K, (K + M), (K + 2M), ------ (K + (N - 1)*M ) where N is the number of elements in the series.3 sum = N * ( (first term + last term) / 2)9 #include <bits/stdc++.h>22#include <bits/stdc++.h>41 #include <bits/stdc++.h>42M, 2M, 3M, ...78 #include <bits/stdc++.h>44#include <bits/stdc++.h>25#include <bits/stdc++.h>25 // C++ program to find the sum of numbers54
Tổng của số chia hết cho 3 là bao nhiêu?Theo quy tắc chia hết cho 3, một số được gọi là chia hết cho 3 nếu tổng các chữ số của số đó chia hết cho 3. For example, the number 495 is completely divisible by 3. The sum of all digits are 4 + 9 + 5 = 18 and 18 is divisible by 3.
Làm cách nào để kiểm tra xem một số có chia hết cho 3 và 5 trong C không?printf("Số chia hết cho 3 và 5 trong khoảng từ 0 đến %d là. \n", số); for (i = 1; i <= num; i++){ nếu (i % 3 == 0 && i % 5 == 0){ printf("%d ", i); Tổng tất cả các số chia hết cho 3 từ 1 đến 100 là bao nhiêu?Giải pháp. Các số tự nhiên từ 1 đến 100 chia hết cho 3 là 3,6,9,…,99. Trình tự nằm trong A. P. Tổng tất cả các số tự nhiên từ 1 đến 100 chia hết cho 3 là 1683 .
Có bao nhiêu số chia hết cho 3?3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69 . Có 33 số có 2 chữ số chia hết cho 3. |
